I would like to simplify
(a == c && c != 0) || (a == 0 && c == 0) to
a == c How can I do that?
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2 Answers
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1 Reduce[(a==c&&c!=0)||(a==0&&c==0),Reals] 
- $\begingroup$ Interesting. Why Reduce[(a==c&&c!=0)||(a==0&&c==0),Complexes] doesn't work? $\endgroup$Cindy9– Cindy92023-11-05 19:41:36 +00:00Commented Nov 5, 2023 at 19:41
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Not assuming a,c \[Element] Reals,
Solve[(a == c && c != 0) || (a == 0 && c == 0), c] // FullSimplify
{{c -> a}}
and
Solve[(a == c && c != 0) || (a == 0 && c == 0), a] // FullSimplify
{{a -> c}}