Considering we have:
acs = <|"A" -> <|"a" -> " ", "aa" -> "asd"|>, "B" -> <|"bb" -> " "|>|> How can we come to have a result as:
res = <|"A" -> <| "aa" -> "asd"|>|> Thanks!
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2 Answers
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2 DeleteCases[Association@KeyValueMap[#1->DeleteCases[#2,_?(StringMatchQ[ToString@#,Whitespace..]&)]&,acs],_?(#==<||>&)] 
- $\begingroup$ Hello Alexey, good to see you here! +1. $\endgroup$Leonid Shifrin– Leonid Shifrin2015-07-08 19:02:19 +00:00Commented Jul 8, 2015 at 19:02
- $\begingroup$ @LeonidShifrin Thank you! $\endgroup$Alexey Golyshev– Alexey Golyshev2015-07-09 03:14:44 +00:00Commented Jul 9, 2015 at 3:14
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Here is a solution, based on pattern matching in the list of rules of the association:
acs //. x_Association :> Normal[x] DeleteCases[ %, (key_->val_String) /; StringMatchQ[val, " "..], Infinity] DeleteCases[ %, _->{}] % /. List->Association (* {A->{a-> ,aa->asd},B->{bb-> }} {A->{aa->asd},B->{}} {A->{aa->asd}} <|A-><|aa->asd|>|> *) 