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Mr.Wizard
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According to the comment below your question I believe this does what you want:

scale = Sign[#] Log[1 + Abs@#] &; invscale = Sign[#] (Exp[Abs@#] - 1) &; ListLinePlot[ llvaluefull, ScalingFunctions -> {{scale, invscale}, Identity} ] 

enter image description here

ScalingFunctions works in ListLinePlot in Mathematica 10.0.2, but it is not officially supported. It may not work in earlier versions.

Mr.Wizard
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