lstIQCodes = IQcodeString.replaceAll(' ','').split(','); I have tried the above code and able to replace spaces and now I want to replace newline as well.
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3 Answers
If you just want to get rid of all the white space, you can just delete it:
lstIQCodes = IQcodeString.deleteWhitespace().split(','); ReplaceAll actually takes a regular expression for the first parameter, so the following is also valid:
lstIQCodes = IQcodeString.replaceAll('\\s+','').split(','); \\s refers to all white space, including tabs, new lines, carriage returns, and spaces.
Or, if you really just wanted spaces and newlines:
lstIQCodes = IQcodeString.replaceAll('[\\n ]+','').split(','); 
- 1Exactly what I would have recommended as well. Using
splitis not really appropriate.2018-06-26 06:32:27 +00:00Commented Jun 26, 2018 at 6:32
You can follow the same approach to remove the new lines as well
for(String lines : IQcodeString.replaceAll(' ','').split(',')) system.debug(lines.replaceAll('\n','').replaceAll('\r','') ); 
Here is a sample utility function for this specifically because of the presence of the legacy carriage return character (ASCII 13) I was seeing in data.
public static String removeAsciiCharFromString(String str, Integer c) { String ret = ''; List<Integer> chars = new List<Integer>(); for (Integer i = 0; i < str.length(); i++) { if (str.charAt(i) != c) { chars.add(str.charAt(i)); } } ret = String.fromCharArray(chars); return ret; } Usage:
String test = String.fromCharArray(new List<Integer> { 65, 13, 65 }); String expected = 'AA'; String actual = UtilConvert.removeAsciiCharFromString(test, 13); System.assertEquals(expected, actual); Of course you can pass in any ASCII value, such as 32 for whitespace.
