How to pass member function as argument in python?

Question

I want to pass something similar to a member function pointer. I tried the following.

class dummy: def func1(self,name): print 'hello %s' % name def func2(self,name): print 'hi %s' % name def greet(f,name): d = getSomeDummy() d.f(name) greet(dummy.func1,'Bala')

Expected output is hello Bala

Community · Accepted Answer · 2017-05-23 10:29:34Z

32

dummy.func1 is unbound, and therefore simply takes an explicit self argument:

def greet(f,name): d = dummy() f(d, name) greet(dummy.func1,'Bala')

edited May 23, 2017 at 10:29

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answered Apr 16, 2012 at 20:50

phihag

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2 Comments

balki Over a year ago

Thanks. btw, what is unbound method?

phihag Over a year ago

It's a method that has no object associated to it. For more information, refer to this stackoverflow question

jtpereyda · Accepted Answer · 2020-04-23 16:26:54Z

Since dummy is the class name, dummy.func1 is unbound.

As phihag said, you can create an instance of dummy to bind the method:

def greet(f,name): d = dummy() f(d, name) greet(dummy.func1, 'Bala')

Alternatively, you can instantiate dummy outside of greet:

def greet(f,name): f(name) my_dummy = dummy() greet(my_dummy.func, 'Bala')

You could also use functools.partial:

from functools import partial def greet(f,name): f(name) my_dummy = dummy() greet(partial(dummy.func1, my_dummy), 'Bala')

hjpotter92 · Accepted Answer · 2012-04-16 20:52:46Z

You can use something like this:

class dummy: def func1(self,name): print 'hello %s' % name def func2(self,name): print 'hi %s' % name def greet(name): d = dummy() d.func1(name) greet('Bala')

and this works perfectly: on codepad

Yes this works but what I am trying to do is to pass the member function too as an argument. i.e greet(dummy.func2,'Bala') should also work

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