Globalize variables in php

Question

I have 2 files. Lets say :

first.php

$a = 'blah'; echo 'echo2='.$a; function foo(){ global $a; echo 'echo3='.$a; return $a; }

second.php

require_once(path/to/the/file/first.php); echo 'echo='.$a; $b = foo(); echo 'echo4='.$b;

running the second.php file I get the following output :

echo=blah echo2=blah echo3= echo4=

My question is "why I can't access variable $a in the function foo !

There's also the syntax error with the require_once. If you don't give the exact code, you'll only get guesses, not answers. Specifically if the include occurs within a functions local variable scope, the $a= declaration won't be global. — mario
– mario, Commented Apr 27, 2012 at 17:20
the register_globals in php.ini is set to off. Thanks for your answers! — Reaver
– Reaver, Commented Apr 27, 2012 at 17:31

Brad · Accepted Answer · 2012-04-27 17:13:59Z

3

Change $global to global. That should fix it.

answered Apr 27, 2012 at 17:13

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Comments

TigerTiger · Accepted Answer · 2012-04-27 17:16:12Z

or use

 $GLOBALS["Your_var_without_dollar_sign"];