Java String remove all non numeric characters but keep the decimal separator

Question

Trying to remove all letters and characters that are not 0-9 and a period. I'm using Character.isDigit() but it also removes decimal, how can I also keep the decimal?

[myStr = myStr.replaceAll( "[^\\d]", "" )][1] [1]: stackoverflow.com/questions/1533659/… — Bitmap
– Bitmap, Commented Apr 29, 2012 at 14:30
This is a strange way to say this. Isn't "all letters and characters that are not 0-9 and a period" equivalent to simpler "all characters that are not 0-9 and a period"? I mean, letters are characters which are not 0-9 nor the period. — Adam Zalcman
– Adam Zalcman, Commented Apr 29, 2012 at 14:30

Andriy M · Accepted Answer · 2012-05-30 06:26:26Z

622

Try this code:

String str = "a12.334tyz.78x"; str = str.replaceAll("[^\\d.]", "");

Now str will contain "12.334.78".

edited May 30, 2012 at 6:26

Andriy M

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answered Apr 29, 2012 at 14:30

Óscar López

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9 Comments

yeaaaahhhh..hamf hamf Over a year ago

This could also work: > str = str.replaceAll("[\\D.]", "");

Pankaj Singhal Over a year ago

@Óscar López: how to include negative numbers also? I mean, I have to replace everything that is not a positive/negative number with an empty space. How to do that?

Óscar López Over a year ago

@PankajSinghal simply include the minus sign in the regex: [^\\d.-]

Óscar López Over a year ago

@yeaaaahhhh..hamfhamf no, that won't work. We have to negate the whole group (including numbers and dots), your suggested code only negates the numbers, and the result won't include dots, as required. Did you test it? using the sample code above, your code returns "1233478", which is incorrect.

Dishank Jindal Over a year ago

i have a array with of numbers and char in it i.e [1,4,7,a,6,d,9,3,5]. I want to filter out all the char from the array. what should i do?

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Peter Lawrey · Accepted Answer · 2012-04-29 14:37:30Z

125

I would use a regex.

String text = "-jaskdh2367sd.27askjdfh23"; String digits = text.replaceAll("[^0-9.]", ""); System.out.println(digits);

prints

2367.2723

You might like to keep - as well for negative numbers.

edited Apr 29, 2012 at 14:37

answered Apr 29, 2012 at 14:31

Peter Lawrey

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6 Comments

Adam Zalcman Over a year ago

You should not escape the dot in your regexp.

Mansour Fahad Over a year ago

Could you please put some explanation for what does ^ and . mean in this statement?

Peter Lawrey Over a year ago

@MansourFahad In a regex [^ means not these characters and inside a [] a . is just a .

Mansour Fahad Over a year ago

Since a . is just a a and doesn’t mean anything, can I just get rid of it?

methodsignature Over a year ago

@MansourFahad only if you want no .s in your result.

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Sergey Vyacheslavovich Brunov · Accepted Answer · 2021-07-06 13:48:56Z

Solution

With dash

String phoneNumberstr = "Tel: 00971-557890-999"; String numberRefined = phoneNumberstr.replaceAll("[^\\d-]", "");

Result: 0097-557890-999.

Without dash

If you also do not need "-" in String you can do like this:

String phoneNumberstr = "Tel: 00971-55 7890 999"; String numberRefined = phoneNumberstr.replaceAll("[^0-9]", "");

Result: 0097557890999.

Robert · Accepted Answer · 2017-03-27 20:52:35Z

27

str = str.replaceAll("\\D+","");

edited Mar 27, 2017 at 20:52

Robert

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answered Mar 27, 2017 at 13:59

Angoranator777

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6 Comments

Zarial Over a year ago

Dunno why people downvoted your solution... Helped me alot, thanks! Votes up!

Angoranator777 Over a year ago

Thanks Zarial, I see Robert actually edited my answer from str = str.replaceAll("\D+",""); to str = str.replaceAll("\\D+",""); ... So i made this mistake when pasting it into StackO's editor box thingy. So thank you Robert for fixing. Now it works!

Saad Benbouzid Over a year ago

it's downvoted cause it's a repost. Exact same answer has already been sublitted 5 years ago !! see above : stackoverflow.com/a/10372905/704246

Boris Treukhov Over a year ago

@SaadBenbouzid huh? what is your definition of the exact same answer?

Boris Treukhov Over a year ago

@SaadBenbouzid 1) that is comment and not an answer 2) that is a completely different regex 3) not all answers which use regex D are identical it's like pointing that all C language answers which use printf() are duplicates. Also if you see an answer in comment you can ask mod to convert it to an answer or even add an answer on your own - answers in comments are discouraged on StackOverlow.

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Kerem Baydoğan · Accepted Answer · 2015-10-01 11:41:05Z

With guava:

String input = "abx123.5"; String result = CharMatcher.inRange('0', '9').or(CharMatcher.is('.')).retainFrom(input);

see http://code.google.com/p/guava-libraries/wiki/StringsExplained

@egorikem if your project is already using guava, you can use it at no extra cost..

Shridutt Kothari · Accepted Answer · 2016-05-25 12:40:02Z

Simple way without using Regex:

Adding an extra character check for dot '.' will solve the requirement:

public static String getOnlyNumerics(String str) { if (str == null) { return null; } StringBuffer strBuff = new StringBuffer(); char c; for (int i = 0; i < str.length() ; i++) { c = str.charAt(i); if (Character.isDigit(c) || c == '.') { strBuff.append(c); } } return strBuff.toString(); }

Since the StringBuffer is only being used inside the function, and not shared between threads, it would be recommended, for performance reasons, to use StringBuilder, instead. See: stackoverflow.com/a/4793503/679240 and stackoverflow.com/a/2771852/679240

Maher Abuthraa · Accepted Answer · 2020-09-25 09:40:54Z

Currency decimal separator can be different from Locale to another. It could be dangerous to consider . as separator always. i.e.

╔════════════════╦═══════════════════╗ ║ Locale ║ Sample ║ ╠════════════════╬═══════════════════╣ ║ USA ║ $1,222,333.44 USD ║ ║ United Kingdom ║ £1.222.333,44 GBP ║ ║ European ║ €1.333.333,44 EUR ║ ╚════════════════╩═══════════════════╝

I think the proper way is:

Get decimal character via DecimalFormatSymbols by default Locale or specified one.
Cook regex pattern with decimal character in order to obtain digits only

And here how I am solving it:

code:

import java.text.DecimalFormatSymbols; import java.util.Locale; public static String getDigit(String quote, Locale locale) { char decimalSeparator; if (locale == null) { decimalSeparator = new DecimalFormatSymbols().getDecimalSeparator(); } else { decimalSeparator = new DecimalFormatSymbols(locale).getDecimalSeparator(); } String regex = "[^0-9" + decimalSeparator + "]"; String valueOnlyDigit = quote.replaceAll(regex, ""); try { return valueOnlyDigit; } catch (ArithmeticException | NumberFormatException e) { Log.e(TAG, "Error in getMoneyAsDecimal", e); return null; } return null; }

I hope that may help,'.

Although this was not asked, but this is the only solution that works with localization.

Michael · Accepted Answer · 2019-03-15 17:41:43Z

For the Android folks coming here for Kotlin

val dirtyString = "💰 Account Balance: $-12,345.67" val cleanString = dirtyString.replace("[^\\d.]".toRegex(), "")

Output:

cleanString = "12345.67"

This could then be safely converted toDouble(), toFloat() or toInt() if needed

David K · Accepted Answer · 2022-07-19 17:46:19Z

The below code should remove all non-digit characters and allow periods.

String newString = currentString.replaceAll("[\\D.]", "");

Orin · Accepted Answer · 2016-11-15 20:14:12Z

A way to replace it with a java 8 stream:

public static void main(String[] args) throws IOException { String test = "ab19198zxncvl1308j10923."; StringBuilder result = new StringBuilder(); test.chars().mapToObj( i-> (char)i ).filter( c -> Character.isDigit(c) || c == '.' ).forEach( c -> result.append(c) ); System.out.println( result ); //returns 19198.130810923. }

Yury · Accepted Answer · 2019-04-01 21:25:23Z

This handles null inputs, negative numbers and decimals (you need to include the Apache Commons Lang library, version 3.8 or higher, in your project):

import org.apache.commons.lang3.RegExUtils; result = RegExUtils.removeAll(input, "-?[^\\d.]");

Library reference: https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/RegExUtils.html

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