What's wrong with the follwing code? How can we make the function print() to work as printf?
#include <stdio.h> #include<stdarg.h> void print(char *format,...) { va_list args; va_start(args,format); printf(format,args); } int main() { print("%d %s",5,"le"); } If you need to pass varargs, then use vprintf instead.
You need vprintf there. Take a look this question, it has a similiar problem: what's the difference between the printf and vprintf function families, and when should I use one over the other?
You probably need to look at vprintf. That function (and the related ones) allow you to pass along a variable argument list, and they handle the formatting.
First of all there is a va_end() call missing which is mandatory if using va_start().
And you cannot use printf() if you want to use a va_list as argument. Take a look at vprintf().
example:
void print(char *format,...) { va_list args; va_start(args,format); vprintf(format,args); va_end(args); } 