How do you check if list is blank? [duplicate]

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Python: What is the best way to check if a list is empty?

def CleanWhiteSpace(theDict): stuff=[] for key,value in theDict.items(): for d in value: if value != " ": stuff.append(d) print d theDict[key]=stuff if not value[d]: print value stuff=[] return theDict print CleanWhiteSpace({'a':['1','2'],'b':['3',' '],'c':[]})

I edited this because I need more help. How do you check if c is blank? Is c is simply equal to []?

I've tried ==[] and "[]" and getting the length and == "", but nothing seems to work.

I (and others) actually used if c in the answers to your previous question. You might learn something by studying these answers carefully. — Sven Marnach
– Sven Marnach, Commented Jun 13, 2012 at 23:47
Trying to get the length as you say was the right idea, that should have worked. — Levon
– Levon, Commented Jun 13, 2012 at 23:47
@WebMaster: If you want an question to be deleted, flag it for moderator attention and provide a good reason why it should be deleted. This question was closed because it's a duplicate. Please take the time to read StackOverflow's FAQ. — Sven Marnach
– Sven Marnach, Commented Jun 14, 2012 at 0:08

jordanm · Accepted Answer · 2012-06-13 23:45:21Z

12

In python, an empty list evaluates to False.

if not c: print "The list is empty" else: print "The list is not empty"

answered Jun 13, 2012 at 23:45

jordanm

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Web Master Over a year ago

doesn't work if not key: del theDict[key] still prints out {'a': ['1', '2'], 'c': [], 'b': ['3', ' ']}

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