get json from HttpResponse

Question

HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://my.server:8080/android/service.php"); List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); nameValuePairs.add(new BasicNameValuePair("action", "getjson")); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost);

service.php generates a json string. How would i fetch it from my response? Btw; I've icluded the GSON library, can i make use of any methods in it perhaps?

Solutions similar to this one looks pretty ugly, imo: best way to handle json from httpresponse android

There much be better ways, right?

Any help is appreciated, thanks

Update:

String json = EntityUtils.toString(response.getEntity());

seems to do the trick. There is just one small issue: The string is wrapped with brackets []. Should i remove them manually? They are generated by php:s json_encode()

Brackets denote a JSON array. You should process the response as such. — Perception
– Perception, Commented Jun 20, 2012 at 23:03
@Perception Correct. I removed my container array from the php code, and its solved the issue. Thanks — Johan
– Johan, Commented Jun 20, 2012 at 23:07
@Johan Could you post your answer and accept it so others may find it useful and know what exactly resolved the issue. Thanks! — Sagar Hatekar
– Sagar Hatekar, Commented Jun 20, 2012 at 23:14

MikeN · Accepted Answer · 2014-03-25 03:16:03Z

I think the problem you are running into is one similar to my own I just ran into. If you run:

 String json_string = EntityUtils.toString(response.getEntity()); JSONObject temp1 = new JSONObject(json_string);

The above code will throw an exception and it looks like the JSON array brackets are to blame. But it's fine to have a JSON array as the top level element! You just need to use JSONArray() instead of JSONObject:

 String json_string = EntityUtils.toString(response.getEntity()); JSONArray temp1 = new JSONArray(json_string);

So you have to know if you are getting a JSONArray or a single dictionary that is a JSONObject in your JSON code.

If you are used to the iOS/Objective-C JSON parsing libraries they use the same top level element to deal with json dictionaries and json array's, so moving to the JAVA / Android world confused me about having two types for handling JSON depending on the top level returned.

user742030 · Accepted Answer · 2012-06-20 23:09:08Z

With this class, you can get the JSON data from either from a server or from your assets folder. It can be easily changed to only one or the other. If you need a Adapter use the one jgilfelt created here on getHub.

@Override public void onActivityCreated(Bundle savedInstanceState) { super.onActivityCreated(savedInstanceState); Bundle getArgs = this.getArguments(); String URI = getArgs.getString(KEY_URI);//OR YOU CAN HARD CODE THIS OR GET THE STRING ANYWAY YOU LIKE. new GetJSONTask().execute(URI); } class GetJSONTask extends AsyncTask<String, Integer, String> { protected String doInBackground(String... arg0) { String uri = arg0[0]; InputStream is = null; if (uri.contains("http") == true) {// Get JSON from URL try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(uri); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); BufferedReader rd = new BufferedReader(new InputStreamReader(is, "UTF-8")); while ((line = rd.readLine()) != null) { json += line; } rd.close(); return json; } catch (Exception e) { e.printStackTrace(); return null; } } else {// Get JSON from Assets Writer writer = new StringWriter(); char[] buffer = new char[1024]; try { InputStream jsonFile = getActivity().getAssets().open(uri); Reader reader = new BufferedReader(new InputStreamReader(jsonFile, "UTF-8")); int n; while ((n = reader.read(buffer)) != -1) { writer.write(buffer, 0, n); } jsonFile.close(); } catch (IOException e) { e.printStackTrace(); } json = writer.toString(); // return JSON String return json; } } @Override protected void onPostExecute(String result) { try { showData(result); } catch (JSONException e) { e.printStackTrace(); Toast.makeText(getActivity(), "something went wrong", Toast.LENGTH_SHORT).show(); } } } private void showData(String json) throws JSONException { JSONObject o = new JSONObject(json); JSONArray data = o.getJSONArray("results"); } }

John J Smith · Accepted Answer · 2012-06-20 23:02:17Z

If I'm returning a JSON string from my web service, I usually want to get it back to a JSON object like so:

String response = client.getResponse(); if (responseCode == 200) { JSONObject obj = new JSONObject(response); }

Looks cleaner, thanks for the input. However, the issue was php related, see my comment above.

Johan · Accepted Answer · 2012-06-20 23:16:36Z

The problem was in my php file. Removing the container array from the json encoded object made my java code work.

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