Having Problems with Arguments

Question

I have tried to write this little script that will batch rename file extensions. I am passing three arguments, the directory where the files are located, the current extension, and the new extension.

The error I am getting is

python batch_file_rename_2.py c:\craig .txt .html Traceback (most recent call last): File "batch_file_rename_2.py", line 13, in <module> os.rename(filename, newfile) WindowsError: [Error 2] The system cannot find the file specified

The code is

import os import sys work_dir=sys.argv[1] old_ext=sys.argv[2] new_ext=sys.argv[3] files = os.listdir(work_dir) for filename in files: file_ext = os.path.splitext(filename)[1] if old_ext == file_ext: newfile = filename.replace(old_ext, new_ext) os.rename(filename, newfile)

possible duplicate of IOError when trying to open existing files — Martijn Pieters
– Martijn Pieters, Commented Aug 6, 2012 at 9:55

Martijn Pieters · Accepted Answer · 2012-08-06 09:51:41Z

os.listdir returns only the filenames, not complete paths. Use os.path.join to recreate the correct path:

for filename in files: file_ext = os.path.splitext(filename)[1] if old_ext == file_ext: newfile = filename.replace(old_ext, new_ext) os.rename( os.path.join(work_dir, filename), os.path.join(work_dir, newfile))

Igor Chubin · Accepted Answer · 2012-08-06 09:52:34Z

You must specify fullname when you are not in the directory (you are not):

os.rename(os.path.join(work_dir, filename), os.path.join(work_dir, newfile))

Fedor Gogolev · Accepted Answer · 2012-08-06 09:52:55Z

Problem is that os.listdir returns only filenames without path, you should use function os.path.join to join work_dir and filename.

And line newfile = filename.replace(old_ext, new_ext) looks very unsafe because it can replace not only extension but some unexpected parts of filename.

You can replace file extension in more safe way using os.path functions, splitext for example.

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