Go xml unmarshalling

Question

Is there a way to extract the source of an image in an HTML file using only one struct (with encode/xml)? Now I have something like this

type XML struct { A Image `xml:"div>img"` } type Image struct { I string `xml:"src,attr"` }

And would be great to only declare something like this :

type Image struct { I string `xml:"div>img,src,attr"` }

This is the HTML :

<div><div><img src="hello.png"/></div></div>

Practically No as HTML is not XML and in real HTML parser must cope with HTML bugs. But XML does not allow bugs and XML is not HTML <img src="hello.png"> is not valid in XML as there is no </img> tag or <img src="hello.png" /> — Max
– Max, Commented Sep 20, 2012 at 21:55
Well truth is that's a typo, now it's corrected (thank you for pointing this out). The question still remains the same. — Inuart
– Inuart, Commented Sep 22, 2012 at 13:26
This issue discusses exactly that for Go 1.2: code.google.com/p/go/issues/detail?id=3633 — dza
– dza, Commented Aug 29, 2013 at 19:02

Inuart · Accepted Answer · 2012-10-05 00:24:51Z

Seems that a good way is to use the exp/html package, like this:

package main import ( "exp/html" "strings" ) func main() { a, _ := html.Parse(strings.NewReader(testString)) println(a.FirstChild.FirstChild.NextSibling.FirstChild.FirstChild.FirstChild.Attr[0].Val) } var testString = `<div><div><img src="hello.png"/></div></div>`

All this FirstChild and NextSibling are needed because exp/html constructs a "correct" html5 tree so this code is actually parsing this:

<html> <head></head> <body> <div> <div> <img src="hello.png"/> </div> </div> </body> </html>

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