Java exception error

Question

My professor asked me to do the following homework in Java, but I'm getting error while trying to execute the code.

Please take a look at the code and let me know what's causing the error? The code is saved into Reverse.java file.

package javaapplication44; import java.util.Scanner; public class Reverse { public static void main (String[] args) { String Fname[] = new String[4]; Scanner s = new Scanner(System.in); for (int i=0; i<=4; i++) { System.out.println("\n Enter Something: "); Fname[i] = s.nextLine(); } System.out.println ("*** The String has been Reversed ***"); for (int i=4; i>0; i--) { System.out.println (Fname[i]); } } }

error text:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at javaapplication44.Reverse.main(Reverse.java:14)

Md. Rizwanul Islam · Accepted Answer · 2012-11-04 10:22:16Z

When u take 4 elements array then u have to count less then 4 Not less than and equal 4. first loop will be conditioned i< 4

And also the second loop will be conditioned i>3

Hope it will work

PermGenError · Accepted Answer · 2012-11-04 10:12:51Z

Array indexes start from zero

change

 for (int i=0; i<=4; i++) {

to

 for (int i=0; i<4; i++) {

also, in your second for loop, start the loop from i=3

 for (int i=3; i>0; i--) {

say if your array is of length 4, the last index would be 3.

just remember this:

 LastINdexOfAnArray = Array_Length -1;

alex · Accepted Answer · 2012-11-04 10:12:34Z

Change...

for (int i=0; i<=4; i++) {

...to...

for (int i=0; i<4; i++) {

You're iterating one beyond the size of your array, getting the ArrayIndexOutOfBoundsException exception.

You also need to account for this in your second loop.

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