multiple command prioritization in bash [duplicate]

Question

Possible Duplicate:
How to wait in bash for several subprocesses to finish and return exit code !=0 when any subprocess ends with code !=0?

I have the following problem:

I have 3 processes that I put in a script

process1 process2 process3

I want that process 1 and 2 run simultaneously but they have both finished before the process 3 starts.

i guess it is something like the following..but I am not sure about that "wait"

#!/bin/sh ( process1 & process2 & wait process3 )

Thank you

Fabio

That will do what you want. You do not need the ( ) construct. — jim mcnamara
– jim mcnamara, Commented Feb 5, 2013 at 11:13

Davide Berra · Accepted Answer · 2013-02-05 11:33:01Z

3

Just save the pid of both processes and wait for both to exit

#!/bin/bash process1 & pid1=$! process2 & pid2=$! wait ${pid1} echo "Return value of process1: $?" wait ${pid2} echo "Return value of process2: $?" process3

edited Feb 5, 2013 at 11:33

answered Feb 5, 2013 at 11:21

Davide Berra

6,6782 gold badges34 silver badges55 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

fabioln79 Over a year ago

so the single wait does not make any sense in your opinion?

Davide Berra Over a year ago

It works as well. This is just my habit and I think it's better because, if you want, you can check the return value of the processes

Collectives™ on Stack Overflow

multiple command prioritization in bash [duplicate]

1 Answer 1

2 Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Linked

Related