Pass multiple parameters in Html.BeginForm MVC

Question

I have something like this:

public ActionResult Create(int clubid) { var club = db.Clubs.Single(c=>c.Id == clubid); ViewBag.Club = club; Competition comp = db.Competitions.Create(); return View(comp) }

and in my .cshtml:

@Model Models.Competition ... @Using(Html.BeginForm()) { ... <input type="submit" value="Save" /> }

This works fine with the following Post Action:

[HttpPost] public ActionResult Create(Competition comp) { if (ModelState.IsValid){...} return RedirectToAction(...); }

However, I want to pass an additional parameter from the @ViewBag.Club object:

[HttpPoSt] public ActionResult Create(int clubid, Competition comp){...}

How do I code this in the BeginForm?

Johan · Accepted Answer · 2013-06-09 20:12:55Z

There are two options here.

a hidden field within the form, or
Add it to the route values parameter in the begin form method.

Edit

@Html.Hidden("clubid", ViewBag.Club.id)

or

 @using(Html.BeginForm("action", "controller", new { clubid = @Viewbag.Club.id }, FormMethod.Post, null)

@I meant more along the line of security, performance or anything? is one an old way or a new way?

JQII · Accepted Answer · 2014-07-30 15:41:39Z

Another option I like, which can be generalized once I start seeing the code not conform to DRY, is to use one controller that redirects to another controller.

public ActionResult ClientIdSearch(int cid) { var action = String.Format("Details/{0}", cid); return RedirectToAction(action, "Accounts"); }

I find this allows me to apply my logic in one location and re-use it without have to sprinkle JavaScript in the views to handle this. And, as I mentioned I can then refactor for re-use as I see this getting abused.

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