Get a list from the dictionary key in a list of dictionaries

Question

I have a list of dictionaries. e.g:

list = [ {list1}, {list2}, .... ]

One of the key-value pair in each dictionary is another dictionary. Ex

list1 = { "key1":"val11", "key2":"val12", "key3":{"inkey11":"inval11","inkey12":"inval12"} } list2 = { "key1":"val21", "key2":"val22", "key3":{"inkey21":"inval21","inkey22":"inval22"} }

I was thinking of getting all values of key3 in the all the dictionaries into a list. Is it possible to access them directly (something like list[]["key3"] ) or do we need to iterate through all elements to form the list?

I have tried

requiredlist = list [ ] ["key3"].

But it doesn't work. The final outcome I wanted is

requiredlist = [ {"inkey11":"inval11","inkey12":"inval12"}, {"inkey21":"inval21","inkey22":"inval22"} ]

What have you tried? Please be sure to read the About for StackOverflow, and the guide to asking good questions. stackoverflow.com/questions/how-to-ask | stackoverflow.com/about — RyPeck
– RyPeck, Commented Aug 15, 2013 at 1:10

Blorgbeard · Accepted Answer · 2013-08-15 01:10:09Z

3

I think a list comprehension would work well here:

[innerdict["key3"] for innerdict in list]

answered Aug 15, 2013 at 1:10

Blorgbeard

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Comments

Óscar López · Accepted Answer · 2013-08-15 02:09:27Z

1

Try this:

list1["key3"]

Notice that list1 and list2 as you defined them are dictionaries, not lists - and the value of "key3" is a set, not a list. You're confounding {} with [], they have different meanings.

edited Aug 15, 2013 at 2:09

answered Aug 15, 2013 at 1:10

Óscar López

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2 Comments

user2672265 Over a year ago

key3 contains not a string called 'dict1' but contains a dictionary called dict1. did you see any quotes around dict1 in the question?

Óscar López Over a year ago

If I write dict1 without quotes, then it won't compile, because it's unhashable and you can't put it in a set. So either way, the sample code in the question won't work. Anyway, I removed that part of my answer, until OP posts some code that makes sense

score 0 · Accepted Answer · 2013-08-15 01:38:19Z

To access an element is a dictionary you must do the following:

dict_name[key_name] #in this case: list1[key3]

Try this:

newlist = [] list = [{ "key1":"val11", "key2":"val12", "key3":{dict1} },{ "key1":"val21", "key2":"val22", "key3":{dict1} }] for innerdict in list: newlist += list(innerdict["key3"]) print newlist #This will give all the values of key3 in all the dictionaries

if dict1 in the lists is a set then the above example will work good, but if it is a dictionary then it will give a list but ONLY the keys will be included so if it is a dictionary try this:

newlist = [] list = [{ "key1":"val11", "key2":"val12", "key3":{dict1} },{ "key1":"val21", "key2":"val22", "key3":{dict1} }] for innerdict in list: newlist.append(innerdict["key3"]) print newlist #This will give all the values of key3 in all the dictionaries

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