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I have a table with a checkbox at the start of each row. Each Checkbox has the ID of #tablecheckbox. The table header row has a check icon which should check all boxed in the table. How can I do this with jQuery?

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  • What have you already tried? Commented Aug 16, 2013 at 5:29
  • 5
    ^^ and ID's should be unique. Commented Aug 16, 2013 at 5:29
  • Make your ids a class, then follow this link: stackoverflow.com/questions/426258/… Commented Aug 16, 2013 at 5:31
  • instead of using id try to use name attriubute it can help to check all check boxs. Commented Aug 16, 2013 at 5:32
  • Can you please show the code for your table (at least the header and a few body rows)? Commented Aug 16, 2013 at 5:38

2 Answers 2

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Here head_checkbox is id of top header and person class is all row checkbox

 $('#head_checkbox').on('change', function () { if ($(this).is(':checked')) { $('.person').attr('checked', true); } else { $('.person').attr('checked', false); } }); $('.person').click(function () { var total_length = $('.person').length; var total_checked_length = $('.person:checked').length; if (total_length == total_checked_length) { $('#head_checkbox').attr('checked', true); } else { $('#head_checkbox').attr('checked', false); } });
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2 Comments

live is deprecated since 1.7 on() should be used instead
I used to set document.getElementById("head_checkbox").checked attribute. Your approach seems more clean. Thanks.
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 $('#head_checkbox').click(function () { if ($(this).is(':checked')) { $('.person').attr('checked', true); } else { $('.person').attr('checked', false); } }); $('.person').click(function () { if ($('.person').length == $('.person:checked').length) { $('#head_checkbox').attr('checked', true); } else { $('#head_checkbox').attr('checked', false); } });
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