c++ pointer to pointer of an int

Question

If I have:

int **p;

why can't I do this?

p = new *int[4];

but if I have:

class T {...} T **c; c = new *T[4];

is that correct?

Mike Seymour · Accepted Answer · 2013-09-10 15:55:34Z

9

The * has to come after the type-name that it modifies:

p = new int*[4]; c = new T*[4];

answered Sep 10, 2013 at 15:46

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2 Comments

Still, why is that not the case with the template?

@JonoRR: I don't see any templates. The second case, with a class type, is just as wrong as the first.

Pierre Fourgeaud · Accepted Answer · 2013-09-10 15:48:52Z

No it is not correct.

the * must go after the type-name.

Then it should be:

p = new int*[4];

And

c = new T*[4];

Paul Evans · Accepted Answer · 2013-09-10 16:08:03Z

You're trying to multiply the keyword new with the type (int or T)! To say you want a new array of pointers to int:

p = new int*[4];

or an array of pointers to T:

c = new T*[4];