Get variable name of object inside the object php

Question

I'm wondering if this was possible and I could not find a way to do it so I ask. How can I get the name of the variable where in a instance of a class is present.

Pseudo code:

class test{ public $my_var_name = ''; function __construct(){ //the object says: Humm I am wondering what's the variable name I am stored in? $this->my_var_name = get_varname_of_current_object(); } } $instance1 = new test(); $instance2 = new test(); $boeh = new test(); echo $instance1->my_var_name . ' '; echo $instance2->my_var_name . ' '; echo $boeh->my_var_name . ' ';

The output would be like:

instance1 instance2 boeh

Why! Well I just wanna know its possible.

Anthony Sterling · Accepted Answer · 2013-10-02 11:53:47Z

I have no idea why, but here you go.

<?php class Foo { public function getAssignedVariable() { $hash = function($object) { return spl_object_hash($object); }; $self = $hash($this); foreach ($GLOBALS as $key => $value) { if ($value instanceof Foo && $self == $hash($value)) { return $key; } } } } $a = new Foo; $b = new Foo; echo '$' . $a->getAssignedVariable(), PHP_EOL; // $a echo '$' . $b->getAssignedVariable(), PHP_EOL; // $b

Good it works, I probably never use it but at least you answered the question.

Community · Accepted Answer · 2017-05-23 12:28:13Z

I created this code trying to answer for How to get name of a initializer variable inside a class in PHP

But it is already closed and referenced to this question,

just another variant easy to read, and I hope I didn't break any basic concept oh php development:

class Example { public function someMethod() { $vars = $GLOBALS; $vname = FALSE; $ref = &$this; foreach($vars as $key => $val) { if( ($val) === ($ref)) { $vname = $key; break; } } return $vname; } } $abc= new Example; $def= new Example; echo $abc->someMethod(); echo $def->someMethod();

Fabio · Accepted Answer · 2013-10-02 11:49:49Z

I can't find a good reason to do that.

Anyways, one way you can do (but again it has no use as far as i can imagine) this is by passing the instance name as a constructor's parameter, like this:

$my_instance = new test("my_instance");

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