Syntax error on simple IF. [duplicate]

Question

Before you ask, I did look at other answers and questions they all seem to be the same and yes I did add it but still nothing. Okay, so I have a program with a menu and at the menu choice it keeps coming up with syntax error at the ":" colon, help please I have tried everything. Here's the code :

def main(): print("Hello and Welcome to the 'Say When' program") print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag") menu = (input("What would you like to search?: ") if menu == '1': print("You chose Class") list = ['Assault', 'Engineer', 'Support', 'Recon'] from random import choice print(choice(list)) elif menu == '2' print("nice")

Error = Syntax error then it highlights the ":" in red.

Your indentation looks wrong, why is the if indented more than the previous line? — Mat
– Mat, Commented Nov 10, 2013 at 16:42
You have an extra ( before input. Also, are you using Pythong 2.x or 3.x? — ratatoskr
– ratatoskr, Commented Nov 10, 2013 at 16:43

aIKid · Accepted Answer · 2013-11-10 16:48:24Z

You're missing a closing parentheses on your input function, which you don't need at all.

menu = input("What would you like to search?: ")

Full fixed code:

def main(): print("Hello and Welcome to the 'Say When' program") print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag") menu = input("What would you like to search?: ") if menu == '1': print("You chose Class") list = ['Assault', 'Engineer', 'Support', 'Recon'] from random import choice print(choice(list)) elif menu == '2': print("nice")

shad0w_wa1k3r · Accepted Answer · 2013-11-10 16:44:09Z

The input() has an unnecessary paranthesis in the beginning.
The if statement is wrongly indented more.
The elif doesn't have a :
Imports must be made at the beginning.

Correct code

from random import choice def main(): print("Hello and Welcome to the 'Say When' program") print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag") menu = input("What would you like to search?: ") if menu == '1': print("You chose Class") list = ['Assault', 'Engineer', 'Support', 'Recon'] print(choice(list)) elif menu == '2': print("nice")

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