How do you pass an array of structs into a function?

Question

Suppose we have:

struct elements{ string drink_name; double price_per_can; double number_in_machine; }; struct elements machine[6];

And machine is populated in main(). How do I pass machine into a function (by reference) to be used inside the function?

Consider using std::array instead of a naked fixed length array. — Captain Obvlious
– Captain Obvlious, Commented Dec 4, 2013 at 23:35

Kerrek SB · Accepted Answer · 2013-12-04 23:44:53Z

5

You can pass it as a reference:

void foo(elements (&x)[6]) { x[1].price_per_can = 1.8; x[4].drink_name = "mom's breakfast juice"; } int main() { elements machine[6]; foo(machine); }

edited Dec 4, 2013 at 23:44

answered Dec 4, 2013 at 23:35

Kerrek SB

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3 Comments

user3064097 Over a year ago

Why am I passing elements into foo() instead of machine?

Stack Exchange Broke The Law Over a year ago

He probably meant machine.

Kerrek SB Over a year ago

@user3064097: Sorry, fixed.

score 1 · Accepted Answer · 2013-12-04 23:39:30Z

std::array<elements, 6> machine_c2; // Edit: Removed const // Edit: Reflect edit by other user // and add consistency with machine.begin() void doSomething(std::array<elements, 6>& machine) { std::cout << machine.begin()->drink_name; machine.begin()->drink_name = "Cherry"; } int main() { machine_c2.begin()->drink_name = "Strawberry"; doSomething(machine_c2); std::cout << machine_c2.begin()->drink_name; return 0; }

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