Printing a special column in a file using awk

Question

I have a problem in printing a column that has names starting with ` (tick).

Below is the content in my file.

abc xyz pqr sym = `WST" abc xyz pqr sym = `WTFC" abc xyz pqr sym = `WTI" abc xyz pqr sym = `WTM" abc xyz pqr sym = `WTR"

I want to print anything after the third column and I'm using the below code:

awk '{{printf "\n"} for(j=4;j<NF;++j){printf " %s",$j}}'

But,I'm not getting the expected output. Its not printing the last column. Could be because of tick character before the name. How can I make it to print the last column as well?

OUTPUT:

sym = sym = sym = sym = sym =

EXPECTED OUTPUT:

sym = `WST" sym = `WTFC" sym = `WTI" sym = `WTM" sym = `WTR"

Here is my command: awk '{{printf "\n"} for(j=4;j<NF;++j){printf " %s",$j}}' — user3158126
– user3158126, Commented Jan 3, 2014 at 17:49

glenn jackman · Accepted Answer · 2014-01-03 17:50:42Z

It's because you're using j < NF instead of j <= NF

Since the field separator seems to be a single space, you could

cut -d " " -f 4- file

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