post variable in ajax

Question

I would like to post the variable var projectid=data.projectid, the same as i did with:

 url: "rapportage/rapport_detail?idKlant=" + klant,

the ajax call look like this:

$.ajax({ type: "POST", url: "rapportage/rapport_detail?idKlant=" + klant, dataType: 'json', error: function(){ alert("Onvoldoende gegevens beschikbaar om rapportage to genereren."); }, success: function(data){ // Plaats data op de juiste plek in de tabel var projectid=data.projectid, titel=data.titel, projecttype =data.projecttype, projectleider =data.projectleider, projecttype =data.projecttype, statusproject =data.statusproject, startproject =data.startproject, deadlineproject =data.deadlineproject, omzetproject =data.omzetproject, kostenproject =data.kostenproject, margeproject =data.margeproject, totaalurenproject =data.totaalurenproject, totaalminutenproject =data.totaalminutenproject, urenkostenproject =data.urenkostenproject; var str=''; for(var i=0,len=titel.length;i<len;i++){ str+="<tr>"+"<td>" + titel[i] + "</td>"; str+="<td>" + projectleider[i] + "</td>"; str+="<td>" + projecttype[i] + "</td>"; str+="<td>" + statusproject[i] + "</td>"; str+="<td>" + startproject[i] + "</td>"; str+="<td>" + deadlineproject[i] + "</td>"; str+="<td>" + "&#8364;" + omzetproject + "</td>"; str+="<td>" + "&#8364;" + kostenproject + "</td>"; str+="<td>" + "&#8364;" + margeproject + "</td>"; str+="<td>" + totaalurenproject + ":" + totaalminutenproject + "</td>"; str+="<td>" + "&#8364;" + urenkostenproject + "</td>"+"</tr>"; } alert(JSON.stringify(data)); $("#details tbody").append(str); } });

Hüseyin BABAL · Accepted Answer · 2014-04-10 10:47:32Z

1

You can use this;

$.ajax({ type: "POST", url: "rapportage/rapport_detail?idKlant=" + klant, dataType: 'json', success: function(data) { var projectid=data.projectid; ........ $.ajax({ type: "POST", url: "rapportage/rapport_detail?idKlant=" + klant, data: "projectid=" + projectid, dataType: 'json', success: function(response) { } } .....

edited Apr 10, 2014 at 10:47

answered Apr 10, 2014 at 10:37

Hüseyin BABAL

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6 Comments

Rene Over a year ago

this doesnt seem to work because the data:projectid has no value there because its done before the var projectid = data.projectid

Hüseyin BABAL Over a year ago

I assumed you have already that variable, so you you want too resend it after first ajax success?

Rene Over a year ago

yes srry:) thats exactly what i wanted to do. i thought about something like this var projectid=data.projectid; $.post("rapportage/rapport_detail?idProject=" + projectid); console.log(projectid);

Hüseyin BABAL Over a year ago

See my updated answer, but you do not need to resend that request again. You can do that in first ajax request at the backend already

Rene Over a year ago

When i do it like that i get an NULL response but when i log it it has values in it.

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Govind Singh · Accepted Answer · 2014-04-10 10:43:28Z

i didn't get what you are asking, but if you want to post a variable by POST then you can

type: "POST", url: "rapportage/rapport_detail", data : {"idKlant" : klan},

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