Symfony - how to generate url with parameters in controller

Question

I want to generate a url like ../profile/firstname.lastname

But i don't understand how i can do this because i want in my php also the id from the user.

this is my controller:

 $controllers ->match('profile/{firstname.lastname}/', array($this, 'profile')) ->assert('userId', '\d+') ->method('GET|POST') ->before(array($this, 'checkLogin')) ->bind('home.profile');

Could you provide a bit more code to help explain the problem you're trying to solve? Where is this code being called? — Jay Sheth
– Jay Sheth, Commented May 16, 2014 at 15:13
I don't have more code because i don't know how to do. Now i can pass the id through the url like profile/1 but i want to pass the names. — user3601546
– user3601546, Commented May 16, 2014 at 15:16
Where did you put that code and what exactly do you want to achieve. Please describe the problem more detailed. You want to generate a URL in a controller-action to ... ? What is that $controllers variable in your code example - the @router service ... or what? — Nicolai Fröhlich
– Nicolai Fröhlich, Commented May 16, 2014 at 16:06

kskaradzinski · Accepted Answer · 2017-05-24 06:06:20Z

You have to build your Route like this

<route id="profile" path="/profile/{first_name}.{last_name}"> <default key="_controller">...</default> </route>

And in controller create like this

$this->generateUrl('profile', [ 'first_name' => 'skowron', 'last_name' => 'line' ]);

but if you have 2 profiles with this same data it will give you bad results. Then you can create slug or add id parameter to your route

Community · Accepted Answer · 2023-11-17 19:56:51Z

Symfony uses Symfony\Component\Routing\Generator\UrlGenerator::generate() to generate paths. But probably the path is not defined in your routing system. So you must create an instance of it and pass a RouteCollection which only contains tha path you want and it does not seem to be a good method.

It's better to use preg_replace.

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