I'm writing a little program but I have a problem with an if else statement.
@echo off set /p points= echo %points% echo 1x5= set /p 15= if %15%==5 ( echo well done! set /a points=%points%+1 ) else ( echo wrong! ) pause echo %points% pause Even if I fill in a wrong answer, it still ads 1 point to my points and says "Well done!"
(BTW: got some problems with inputting the code, don't now if you will be able to read it)
When an argument is included in the command line when calling the batch file, it is referenced from code as %1, %2, ... for the first, second, ... parameters.
In your code, when you write if %15%==5 ..., %15% is interpreted as first parameter to batch file (%1) followed by a 5 and a non escaped non paired percent sign that is discarded by the parser. So, if the batch file has no input arguments and %1 is empty, your if code is executed as if 5==5 ...
As a general recomendation, variables in batch files "should" never start with a number, as they will be considered as input arguments.
@echo off setlocal enableDelayedExpansion set /p points= echo %points% echo 1x5= set /p 15= if !15!==5 ( echo well done! set /a points=!points!+1 ) else ( echo wrong! ) pause echo !points! endlocal pause MC MD explained why your code does not work.Here's a way to make it work.
