#include<stdio.h> int main() { printf("He %c llo",65); } Output: He A llo
#include<stdio.h> int main() { printf("He %c llo",13); } Output: llo. It doesnt print He.
I can understand that 65 is ascii value for A and hence A is printed in first case but why llo in second case.
Thanks
ASCII 13 is carriage return, which on some systems simply moves the cursor to the beginning of the line you were just on.
Further characters then wipe out the earlier text.
Man ascii:
Oct Dec Hex Char 015 13 0D CR '\r' Character 13 is carriage return so it prints He then returns to the beginning of the line and prints the remining llo.
It's just being rendered strangely due to the nature of a carriage return*. You can see the characters that are output, by piping to another tool such as xxd:
$ gcc b.c && ./a.out | xxd 0000000: 4865 200d 206c 6c6f He . llo $ gcc c.c && ./a.out | xxd 0000000: 4865 2041 206c 6c6f He A llo
* See Wikipedia:
On printers, teletypes, and computer terminals that were not capable of displaying graphics, the carriage return was used without moving to the next line to allow characters to be placed on top of existing characters to produce character graphics, underlines, and crossed out text.
Aor is itHe A llo?