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I have got the following Problem.

I´m doing a grep like:

$command = grep -r -i --include=*.cfg 'host{' /omd/sites/mesh/etc/icinga/conf.d/objects

I got the following output:

/omd/sites/mesh/etc/icinga/conf.d/objects/testsystem/test1.cfg:define host{ /omd/sites/mesh/etc/icinga/conf.d/objects/testsystem/test2.cfg:define host{ /omd/sites/mesh/etc/icinga/conf.d/objects/testsystem/test3.cfg:define host{ ...

for all *.cfg files.

With exec($command,$array)

I passed the result in an array.

Is it possible to get only the filenames as result of the grep-command.

I have tried the following:

$Command= grep -l -H -r -i --include=*.cfg 'host{' /omd/sites/mesh/etc/icinga/conf.d/objects

but I got the same result.

I know that on the forum a similar topic exists.(How can I use grep to show just filenames (no in-line matches) on linux?), but the solution doesn´t work.

With "exec($Command,$result_array)" I try to get an array with the results. The mentioned solutions works all, but I can´t get an resultarray with exec().

Can anyone help me?

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3 Answers 3

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18

Yet another simpler solution:

grep -l whatever-you-want | xargs -L 1 basename

or you can avoid xargs and use a subshell instead, if you are not using an ancient version of the GNU coreutils:

basename -a $(grep -l whatever-you-want)

basename is the bash straightforward solution to get a file name without path. You may also be interested in dirname to get the path only.

GNU Coreutils basename documentation

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5

Is it possible to get only the filenames as result of the grep command.

With grep you need the -l option to display only file names.

Using find ... -execdir grep ... \{} + you might prevent displaying the full path of the file (is this what you need?)

find /omd/sites/mesh/etc/icinga/conf.d/objects -name '*.cfg' \ -execdir grep -r -i -l 'host{' \{} +

In addition, concerning the second part of your question, to read the result of a command into an array, you have to use the syntax: IFS=$'\n' MYVAR=( $(cmd ...) )

In that particular case (I formatted as multiline statement in order to clearly show the structure of that expression -- of course you could write as a "one-liner"):

IFS=$'\n' MYVAR=( $( find objects -name '*.cfg' \ -execdir grep -r -i -l 'host{' \{} + ) )

You have then access to the result in the array MYVAR as usual. While I while I was testing (3 matches in that particular case):

sh$ echo ${#MYVAR[@]} 3 sh$ echo ${MYVAR[0]} ./x y.cfg sh$ echo ${MYVAR[1]} ./d.cfg sh$ echo ${MYVAR[2]} ./e.cfg # ...
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3 Comments

Your suggested string works! Thank you. I have got one more question: -I try to get the result as an array -I tried to execute your string as following: $shellCommand=find /omd/sites/mesh/etc/icinga/conf.d/objects -name '*.cfg' \ -execdir grep -r -i -l 'host{' \{} + <br /> exec($shellCommand, $hostname);
@ThomasLang Like the other answerers, I missed the second part of your question. Maybe you should have posted two separate questions? Anyway I've fixed my answer to add that part. Hope this help.
at the second look at my question I saw that I have forgotten the second part. So I added it later. I hope this was not to confusing.
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This should work:

grep -r -i --include=*.cfg 'host{' /omd/sites/mesh/etc/icinga/conf.d/objects | \ awk '{print $1}' | sed -e 's|[^/]*/||g' -e 's|:define$||'

The awk portion finds the first field in it and the sed command trims off the path and the :define.

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