Initialize Array C++

Question

I have the code to print out time in the following format: 00 01 02 03 04 05 06 07 08 09 10 11... only that the first number (0) needs to be above the second number (0).. Below is what I have

#include <iostream> using namespace std; void printArray (int arg[], int length) { for (int n=0; n<length; ++n) cout << arg[n] << ' '; cout << '\n'; } int main() { int ftime[99] = {0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,2}; int ttime[99] = {0,1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0}; cout << "Time: ";printArray(ftime,21); cout << " ";printArray(ttime, 21); return 0; }

Now the following prints out:

Time: 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 2 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0

Which is exactly what I want, but I need to do this all the way to 99 and was wondering if there is an easier way to initialize both the ftime and ttime arrays other than the way I did it. Any input would be greatly appreciated!

"if there is an easier way to initialize both" Depends on the number schemes you need to store in the arrays. — πάντα ῥεῖ
– πάντα ῥεῖ, Commented Oct 30, 2014 at 18:47
Can't you just loop to create the arrays? We are actually not sure why you created a restriction for yourself by trying to initialize the array during declaration — Titus
– Titus, Commented Oct 30, 2014 at 18:50

merlin2011 · Accepted Answer · 2014-10-30 18:55:06Z

Just feed it with a loop.

#include <iostream> using namespace std; void printArray (int arg[], int length) { for (int n=0; n<length; ++n) { cout << arg[n] << ' '; } cout << '\n'; } int main() { int ftime[100]; int ttime[100]; for (int i = 0; i < 100; i++) { ftime[i] = i / 10; ttime[i] = i % 10; } cout << "Time: "; printArray(ftime,100); cout << " "; printArray(ttime,100); return 0; }

The initial ftime for this one is a 9 instead of a 0.. so it starts as 09 01 02 03...

Rosme · Accepted Answer · 2014-10-30 18:53:34Z

Simple loop would do it.

int j = -1; for(unsigned int i = 0; i < 99; ++i) { ttime[i] = i % 10; if(i % 10 == 0) { ++j; } ftime[i] = j; }

Dr. Debasish Jana · Accepted Answer · 2014-10-30 18:51:22Z

something like this?

int ftime[99]; int i; for (i=0; i < 99; i++) { if (i/2 == 1) ftime[i] = 1; else if (i==20) ftime[i] = 2; else ftime[i] = 0; } for (i=0; i < 99; i++) { if (i/2 < 2) ttime[i] = i % 10; else ttime[i] = 0; }

Richard · Accepted Answer · 2014-10-30 18:56:15Z

You could do a dual-layered for-statment example:

int k = 0; for(int i = 0; i < 9, i++){ for(int j = 0; j < 9, j++){ ftime[k] = i; ttime[k] = j; k++; } }

Remember K.I.S.S.

Yazan · Accepted Answer · 2014-10-30 18:58:42Z

this should fix it

#include <iostream> using namespace std; void printArray (int arg[], int length) { for (int n=0; n<length; ++n) cout << arg[n] << ' '; cout << '\n'; } int main() { int ftime[99]; int ttime[99]; for(int j=0; j < 99; j++) { ftime[j] = j/10; ttime[j] = j%10; } cout << "Time: ";printArray(ftime,99); cout << " ";printArray(ttime, 99); return 0; }

bhargavi kotapati · Accepted Answer · 2014-10-30 19:04:25Z

declare both as integers and use the following for loop

for(int i=0;i<100;i++); { ftime[i]=i/10; ttime[i]=i%10; }

Akshay Rao · Accepted Answer · 2014-10-30 19:46:51Z

#define MAX 99 int ftime [MAX+1]; // Includes 00 too int ttime [MAX+1]; // Includes 00 too for (int ctr = 0; ctr < MAX+1, ctr++) { ftime[ctr] = floor(ctr/10); ttime[ctr] = ctr % 10; // modulus oper }

This may have syntax errors, sorry. Didn't have a c-compiler handy on this computer of mine.

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