This function has been asked a few times on here but I am interested in a particular case. Is it possible to have the size of the array passed defined by an additional argument?
As an example, let's say I want a function to print a 2D array. However, I the array may not have the same dimensions every time. It would be ideal if I could have additional arguments define the size of that array. I am aware that I could easily switch out the n for a number here as needed but if I have more complex functions with separate header files it seems silly to go and edit the header files every time a different size array comes along. The following results in error: use of parameter 'n' outside function body... which I understand but would like to find some workaround. I also tried with g++ -std=c++11 but still the same error.
#include <iostream> using namespace std; void printArray(int n, int A[][n], int m) { for(int i=0; i < m; i++){ for(int j=0; j<n; j++) { cout << A[i][j] << " "; } cout << endl; } } int main() { int A[][3] = { {1,2,3}, {4,5,6}, {7,8,9}, {10,11,12} }; printArray(3, A, 4); return 0; } Supposedly, this can be done with C99 and also mentioned in this question but I cannot figure out how with C++.