So I declared a variable as an integer and initialized it to 0. When I tried printing the value of that variable, it gave me an incredibly high number. int
x=0; printf("%d", &x); This is what I did. Am I doing anything wrong? Thanks in advance.
4 Answers
The operator '&' represent the address of that variable. we need, the actual value of that variable use like this...
printf("%d",x); 
Comments
When we are using the &x, it will refer the address of the x . we need to print the value of x then use this,
printf("%d", x); In scanf() function, only we need to use &x, to locate the memory address to store the value.
1 Comment
Melt
Oh okay. I completely forgot about that. Thanks :)
You print the address of the x so it will print the address during the compile time it will display the warning warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’ [-Wformat]
So use following
printf("%d",x);
Comments
Please print the value of X instead address like printf("%d",x);
