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I have a little function that shows latest activity, it grab timestamp in unix format from the db, and then it echo out with this line:

 date("G:i:s j M -Y", $last_access)

Now i would like to replace the date (j M -Y) to Yesterday, and Today if the latest activity was within today, and same goes with Yesterday.

How can i do this?

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  • 1
    Do you have any code that you've written so far? Commented Aug 10, 2010 at 23:29
  • Can you please try to be more precise? I haven't understood what you mean by Yesterday and Today... frankly ;-) Commented Aug 10, 2010 at 23:36
  • 2
    It's tomorrow you need to worry about, not yesterday or today, clearing away all those cobwebs and the sorrow, just knowing it's a day away and all that. Commented Aug 10, 2010 at 23:42

12 Answers 12

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45

I would find the timestap for last midnight and the one before it, if $last_access is between the two timestamps, then display yesterday, anything greater than last midnight's timestamp would be today...

I believe that would be the quicker than doing date arithmetic.

Actually, I just tested this code and it seems to work great:

<?php if ($last_access >= strtotime("today")) echo "Today"; else if ($last_access >= strtotime("yesterday")) echo "Yesterday"; ?>
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15 
function get_day_name($timestamp) { $date = date('d/m/Y', $timestamp); if($date == date('d/m/Y')) { $date = 'Today'; } else if($date == date('d/m/Y',now() - (24 * 60 * 60))) { $date = 'Yesterday'; } return $date; } print date('G:i:s', $last_access).' '.get_day_name($last_access);
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6 Comments

The else if line seems to be missing a ).
Sorry, fixed that up for you Karem. I guess it worked out for you though.
Function now() does not exists. Use time()
It's probably easier to once get the number of days away from now instead, so the same value can be used twice.
shouldn't it be return $day_name; ?
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11

You have to compare day with day, secondes comparaison are totally wrong :

If we are today morning, that means yesterday night is today (by minus 24h) ^^

Here a method I use for Kinoulink ( a french startup ) :

public function formatDateAgo($value) { $time = strtotime($value); $d = new \DateTime($value); $weekDays = ['Lundi', 'Mardi', 'Mercredi', 'Jeudi', 'Vendredi', 'Samedi', 'Dimanche']; $months = ['Janvier', 'Février', 'Mars', 'Avril',' Mai', 'Juin', 'Juillet', 'Aout', 'Septembre', 'Octobre', 'Novembre', 'Décembre']; if ($time > strtotime('-2 minutes')) { return 'Il y a quelques secondes'; } elseif ($time > strtotime('-30 minutes')) { return 'Il y a ' . floor((strtotime('now') - $time)/60) . ' min'; } elseif ($time > strtotime('today')) { return $d->format('G:i'); } elseif ($time > strtotime('yesterday')) { return 'Hier, ' . $d->format('G:i'); } elseif ($time > strtotime('this week')) { return $weekDays[$d->format('N') - 1] . ', ' . $d->format('G:i'); } else { return $d->format('j') . ' ' . $months[$d->format('n') - 1] . ', ' . $d->format('G:i'); } }
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Great! It's only missing the year, at the last «else». But it's a beauty. Thanks!
5

I enhanced Thomas Decaux answer to come up with this

function formatTimeString($timeStamp) { $str_time = date("Y-m-d H:i:sP", $timeStamp); $time = strtotime($str_time); $d = new DateTime($str_time); $weekDays = ['Mon', 'Tue', 'Wed', 'Thur', 'Fri', 'Sat', 'Sun']; $months = ['Jan', 'Feb', 'Mar', 'Apr', ' May', 'Jun', 'Jul', 'Aug', 'Sept', 'Oct', 'Nov', 'Dec']; if ($time > strtotime('-2 minutes')) { return 'Just now'; } elseif ($time > strtotime('-59 minutes')) { $min_diff = floor((strtotime('now') - $time) / 60); return $min_diff . ' min' . (($min_diff != 1) ? "s" : "") . ' ago'; } elseif ($time > strtotime('-23 hours')) { $hour_diff = floor((strtotime('now') - $time) / (60 * 60)); return $hour_diff . ' hour' . (($hour_diff != 1) ? "s" : "") . ' ago'; } elseif ($time > strtotime('today')) { return $d->format('G:i'); } elseif ($time > strtotime('yesterday')) { return 'Yesterday at ' . $d->format('G:i'); } elseif ($time > strtotime('this week')) { return $weekDays[$d->format('N') - 1] . ' at ' . $d->format('G:i'); } else { return $d->format('j') . ' ' . $months[$d->format('n') - 1] . (($d->format('Y') != date("Y")) ? $d->format(' Y') : "") . ' at ' . $d->format('G:i'); }

}

It takes in the time stamp as the argument, it adds the year of the time if it was from a different year, etc...

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I am glad to help
3 
echo date("Y:m:d",strtotime("today")); echo date("Y:m:d",strtotime("yesterday"));
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Hi! While this may be a solution to the question, code only answers are generally discouraged on SO. Please take some time to edit your response with an explanation as to why this is a solution as it will help OP and future visitors of the site.
2

If you are going down the road as suggested above, with unix timestamps for today / yesterday, have a look at strtotime, one of the greatest inventions of the 20th (or 21st?) century:

echo strtotime("yesterday"); // midnight 1281391200 echo strtotime("today"); // midnight 1281477600 echo strtotime("today, 1:30"); 1281483000
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1 
something like: $now = time(); $last_midnight = $now - ($now % (24*60*60)); if ($last_access >= $last_midnight) { print "Today"; } elseif ($last_access >= ($last_midnight-(24*60*60)) { Print "Yesterday"; }
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@mvds: I didn't know you could use relative strings in strtotime. Nice. Some gotchas re PHP4 vs PHP5 though.
I actually use it in some web based search service to allow the user to enter a sliding window: e.g. from "two months ago" to "today".
1

we can get Date Difference using diff method of DateTime class.

<?php $date1 = new DateTime("2022-07-26"); $date2 = new DateTime("2022-07-27"); $days = $date2->diff($date1)->format('%r%d'); if($days === 0) { return 'Today'; } else if($days === "-1") { return 'yesterday'; }else { return $days . ' days later'; } ?>

for more details see

  1. this answer
  2. PHP doc example
  3. How to calculate the difference between two dates
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0

here's working function 

 function minus_one_day($date){ $date2 = formatDate4db($date); $date1 = str_replace('-', '/', $date2); $yesterday = date('Y-m-d',strtotime($date1 . "-1 days")); return $yesterday; }

hope work for you...

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0 
$today=new DateTime('now'); $yesterday=date($today,strtotime("-1 day"));
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Can you explain that further? Most other answers need some kind of comparison to print either Yesterday or Today, but your code is missing it - are you sure this solves the given problem?
$today=new DateTime('now'); $yesterday=date($today,strtotime("-1 day")); maybe not wokıing ...
That looks like the same code you've posted in your answer. But how does it print something? How does it print either the exact string Yesterday or Today?
0 
date('d.m.Y',strtotime("-1 days"));
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This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker. - From Review
0

Persian type:

function time_elapsed_string($datetime, $full = false) { $now = new DateTime; $ago = new DateTime($datetime); $diff = $now->diff($ago); $diff->w = floor($diff->d / 7); $diff->d -= $diff->w * 7; $string = array( 'y' => 'سال', 'm' => 'ماه', 'w' => 'هفته', 'd' => 'روز', 'h' => 'ساعت', 'i' => 'دقیقه', 's' => 'ثانیه', ); foreach ($string as $k => &$v) { if ($diff->$k) { $v = $diff->$k . ' ' . $v . ($diff->$k > 1 ? ' روز' : ''); } else { unset($string[$k]); } } if (!$full) $string = array_slice($string, 0, 1); return $string ? implode(', ', $string) . ' قبل' : 'اکنون'; }
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