Swift - Remove white spaces from string doesn't work

Question

i'm trying to remove white spaces and some characters from a string, please check my code below

// giving phoneString = +39 333 3333333 var phoneString = ABMultiValueCopyValueAtIndex(phone, indexPhone).takeRetainedValue() as! String // Remove spaces from string phoneString = phoneString.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet()) // Remove +39 if exist if phoneString.rangeOfString("+39") != nil{ phoneString = phoneString.stringByReplacingOccurrencesOfString("\0", withString: "+39", options: NSStringCompareOptions.LiteralSearch, range: nil) } print(phoneString) // output +39 333 3333333

it seems like all the changes has no effect over my string, why this happen?

EDIT @V S

EDIT 2:

I tried to convert my string in utf 8, check the result:

43 51 57 194 160 51 51 51 194 160 51 51 51 51 51 51 51

where:

43 = + 51 = 3 57 = 9 160 = space 194 = wtf?!? is this?

Abhishek · Accepted Answer · 2018-07-22 21:07:43Z

what do you try to do is

// your input string let str = "+39 333 3333333" let arr = str.characters.split(" ").map(String.init) // ["+39", "333", "3333333"] // remove country code and reconstruct the rest as one string without whitespaces let str2 = arr.dropFirst().joinWithSeparator("") // "3333333333"

to filter out country code, only if exists (as Eendje asks)

let str = "+39 123 456789" let arr = str.characters.split(" ").map(String.init) let str3 = arr.filter { !$0.hasPrefix("+") }.joinWithSeparator("") // "123456789"

UPDATE, based on your update. 160 represents no-breakable space. just modify next line in my code

let arr = str.characters.split{" \u{00A0}".characters.contains($0)}.map(String.init)

there is " \u{00A0}".characters.contains($0) expression where you can extend the string to as much whitespace characters, as you need. 160 is \u{00A0} see details here.

Update for Swift 4

String.characters is deprecated. So the correct answer would now be

// your input string let str = "+39 333 3333333" let arr = str.components(separatedBy: .whitespaces) // ["+39", "333", "3333333"] // remove country code and reconstruct the rest as one string without whitespaces let str2 = arr.dropFirst().joined() // "3333333333"

@Mono.WTF 160 represents unicode no-break space .... OK, I see now your trouble, will update my answer in few minutes :-)
@Mono.WTF sometimes we do not see the forest for the trees , it becomes :-)
can anyone tell why it doesn't replace the whitespace in the first place?

subjective_c · Accepted Answer · 2017-09-21 07:37:38Z

Swift 3 / Swift 4

let withoutSpaces = phoneNumber.replacingOccurrences(of: "\\s", with: "", options: .regularExpression)

Grimxn · Accepted Answer · 2016-02-18 11:49:43Z

Firstly, stringByTrimmingCharactersInSet only trims the string - i.e. removes leading & trailing spaces - you need to use stringByReplacingOccurrencesOfString replacing " " with "".

Secondly, your parameters on stringByReplacingOccurrencesOfString for the country code are the wrong way round.

Thirdly, "\0" is not what you want- that's ASCII null, not zero.

Shakeel Ahmed · Accepted Answer · 2019-06-19 09:28:56Z

Swift 5

//MARK:- 3 ways to resolve it var tempphone = "0345 55500 93" //MARK:- No 1 tempphone = tempphone.replacingOccurrences(of: " ", with: "") //MARK:- No 2 tempphone = tempphone.replacingOccurrences(of: "\\s", with: "", options: .regularExpression) //MARK:- No 3 tempphone = tempphone.trimmingCharacters(in: .whitespaces)

Chatar Veer Suthar · Accepted Answer · 2016-02-18 11:49:46Z

1

phoneString = phoneString.stringByReplacingOccurrencesOfString("+39", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil) phoneString = phoneString.stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())

answered Feb 18, 2016 at 11:49

Chatar Veer Suthar

15.6k26 gold badges94 silver badges158 bronze badges

3 Comments

Chatar Veer Suthar Over a year ago

@Mono.WTF, Check it.

Mono.WTF Over a year ago

same output, nothing changes

Chatar Veer Suthar Over a year ago

Can I see Log, print phoneString, before first line, after first line and last. and add Screenshot,

TechBee · Accepted Answer · 2016-02-18 12:03:49Z

Try this. This has worked for me:

if phoneString.rangeOfString("+39") != nil{ freshString = phoneString.stringByReplacingOccurrencesOfString("\0", withString: "+39", options: NSStringCompareOptions.LiteralSearch, range: nil) } var strings = freshString.componentsSeparatedByString(" ") as NSArray var finalString = strings.componentsJoinedByString("") //outputs +393333333333

ferbass · Accepted Answer · 2017-03-07 00:34:18Z

You can use this replace the whitespace

phoneNumber.replacingOccurrences(of: "\u{00A0}", with: "")

Prabhu.Somasundaram · Accepted Answer · 2016-02-18 11:48:03Z

0

let trimmedPhoneString = String(phoneString).stringByTrimmingCharactersInSet(NSCharacterSet.whitespaceCharacterSet())

To Remove +39 if exist, you can use stringByReplacingOccurrencesOfString instead

answered Feb 18, 2016 at 11:48

Prabhu.Somasundaram

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2 Comments

Mono.WTF Over a year ago

same output, nothing changes

Prabhu.Somasundaram Over a year ago

Dude, stringByTrimmingCharactersInSet can trim the trailing or leading white spaces if any. check the apple docs. As i said you can use stringByReplacingOccurrencesOfString

Pradeep K · Accepted Answer · 2016-02-18 12:12:56Z

var phoneString = "+39 333 3333333" phoneString = phoneString.stringByReplacingOccurrencesOfString(" ", withString:"") if phoneString.rangeOfString("+39") != nil { phoneString = phoneString.stringByReplacingOccurrencesOfString("+39", withString: "", options: NSStringCompareOptions.LiteralSearch, range: nil) } print(phoneString) // output 3333333333

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