Regex to extract word inside round brackets

Question

I have been stuck with this regex issue for a long time now. I have the following string.

[{"op": "replace", "path": "/endDate", "value": "#{$PurchaseOrderExtensions.findOne(_extid).getEndDate().toString()}"}]

I am totally confused how to extract the word _extid which is within the round brackets. The confusing part is that there are many round brackets. I need to extract only the one after the occurrence of findOne.

I tried the following regular expressions but none of them even matched the string to extract the one after findOne.

/\{(\(\w+\))\}/? /\\((\\w+)\\)/? and many more...

What mistake am I doing here?

"What mistake am I doing here?" you're not using a JSON parser is one thing. The fact you have code inside of your string is another bad thing; likely to be evald later or some kind of dynamic execution. — Ash
– Ash, Commented Apr 13, 2016 at 16:25
are you saying the extid is the data, which may change? you want to get to findOne(whaterver is here) ? — Scott Weaver
– Scott Weaver, Commented Apr 13, 2016 at 16:44
@ash I know how to use JSON parsing. But I am using Xtend, which does not support any JSON parsing like we use in basic Java. In fact, it does not allow to add any extra java jars. And I do not think "not using JSON parser" is a mistake. It is a choice. Plus I have put in this code in this string with some purpose. — Philip John
– Philip John, Commented Apr 13, 2016 at 21:15

Alfeu · Accepted Answer · 2016-04-13 16:20:08Z

You may just find for findOne in your regex:

findOne\((\w+)\)

Then you can get your string from the inner capture group.

JJoao · Accepted Answer · 2016-04-13 16:23:02Z

'(?<=findOne)\(.*?\)'

Example

grep -Po '(?<=findOne)\(.*?\)' file

or

grep -Po 'findOne\K\(.*?\)' file

Adassko · Accepted Answer · 2016-04-13 16:10:38Z

Why won't you just include findOne into your expression?

Like:

/\.findOne\((.*?)\)/

depending on the language and use, you may need to double the backslashes, or as mentioned - just use JSON parser

prw416 · Accepted Answer · 2016-04-13 16:14:59Z

Could you use something like this that captures what is inside round brackets:

\([a-z1-9_]*\)

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