scala: overriding equals of basic types

Question

I've defined a wrapper class:

class Wrapper[T](private val value: T)

and I want to make sure that w(v1) == v2 and v2 == w(v1) iff v1 == v2. The first part is easy because you can override equals method of Wrapper class. But the problem is the other way around, making 5 == Wrapper(5) return true for example, achieving symmetry of equality. Is it possible in scala that you can override equals method of basic types like Int or String? In C++, you can override both operator==(A, int) and operator==(int, A) but it doesn't seem so with java or scala.

First part IMO is also not easy: equals has signature equals(x: Any): Boolean and T is erased. — Victor Moroz
– Victor Moroz, Commented Sep 4, 2016 at 2:36
Do you really need ==? It's easy to define a standalone method in both directions, or define another method implicitly. You can't really override == in Int as it's already there. — Victor Moroz
– Victor Moroz, Commented Sep 4, 2016 at 3:14

Victor Moroz · Accepted Answer · 2016-09-04 03:19:32Z

How it can possibly be done with implicits (note that neither == nor equals can be used here):

import scala.reflect.ClassTag implicit class Wrapper[T : ClassTag](val value: T) { def isEqual(other: Any) = other match { case x: T => x == value case x: Wrapper[T] => x.value == value case _ => false } } 5 isEqual (new Wrapper(5)) // true (new Wrapper(5)) isEqual 5 // true

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