Is it possible to capture any traceback generated by a Python application?

Question

I've been searching google for a way to somehow capture any traceback generated by a Python application.

I'd like to send an email/slack/notification to myself if any error occurs which generates a traceback (instead of relying on users to report issues to me).

I still haven't found anything which doesn't involve you doing a try/except. But of course I can't put everything I do inside individual try/except clauses since I'm writing applications which launch a UI (PySide/PyQt4/PySide2/PyQt5) and could error on user interaction.

Is this possible, and if so how can I capture any traceback generated?

You could parse the logs which would detect an exception and send you an email. Or, you can try using sentry pypi.python.org/pypi/sentry? — Nehal J Wani
– Nehal J Wani, Commented Oct 2, 2016 at 9:04

Łukasz Rogalski · Accepted Answer · 2016-10-02 10:33:04Z

You can easily do it by creating custom sys.excepthook:

import sys import traceback def report_exception(exc_type, exc_value, exc_tb): # just a placeholder, you may send an e-mail here print("Type", exc_type) print("Value", exc_value) print("Tb", ''.join(traceback.format_tb(exc_tb))) def custom_excepthook(exc_type, exc_value, exc_tb): report_exception(exc_type, exc_value, exc_tb) sys.__excepthook__(exc_type, exc_value, exc_tb) # run standard exception hook sys.excepthook = custom_excepthook raise RuntimeError("I want to report exception here...")

For pretty-printing traceback objects refer to traceback module.

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