How do you convert a hex string to short in c++?
Let's say you have
string hexByte = "7F"; How do you convert that to a byte? Which I assume it's a char or int8_t in c++
I tried:
wstring hexString = "7F"; unsigned char byte; stringstream convert(hexString); convert >> byte; 
// converting from UTF-16 to UTF-8 #include <iostream> // std::cout, std::hex #include <string> // std::string, std::u16string #include <locale> // std::wstring_convert #include <codecvt> // std::codecvt_utf8_utf16 int main () { std::u16string str16 (u"\u3084\u3042"); // UTF-16 for YAA (やあ) std::wstring_convert<std::codecvt_utf8_utf16<char16_t>,char16_t> cv; std::string str8 = cv.to_bytes(str16); std::cout << std::hex; std::cout << "UTF-8: "; for (char c : str8) std::cout << '[' << int(static_cast<unsigned char>(c)) << ']'; std::cout << '\n'; return 0; } http://www.cplusplus.com/reference/locale/wstring_convert/to_bytes/
Convert each character of hex input to integer type
int char2int(char input) { if(input >= '0' && input <= '9') return input - '0'; if(input >= 'A' && input <= 'F') return input - 'A' + 10; if(input >= 'a' && input <= 'f') return input - 'a' + 10; throw std::invalid_argument("Invalid input string"); } // This function assumes src to be a zero terminated sanitized string with // an even number of [0-9a-f] characters, and target to be sufficiently large void hex2bin(const char* src, char* target) { while(*src && src[1]) { *(target++) = char2int(*src)*16 + char2int(src[1]); src += 2; } } 
int8_tonly exists if you have 8 bits per byte. Show your code. Did you even made some effort on your own? Note: using unsigned types will make your life much easier.std::istringstreamusing thestd::hexI/O manipulator.classkeyword.