Sending an Email with python using the SMTP Library

Question

import smtplib def prompt(prompt): return raw_input(prompt).strip() fromaddr = prompt("From: ") toaddrs = prompt("To: ").split() print "Enter message, end with ^D (Unix) or ^Z (Windows):" msg = ("From: %s\r\nTo: %s\r\n\r\n" % (fromaddr, ", ".join(toaddrs))) while 1: try: line = raw_input() except EOFError: break if not line: break msg = msg + line print "Message length is " + repr(len(msg)) server = smtplib.SMTP('smtp.live.com:25') server.set_debuglevel(1) server.sendmail(fromaddr, toaddrs, msg) server.quit()

I'm trying to send an Email using that example, but it doesnt work, I dont get any error it just doesn't send anything, I'm trying to send it to a hotmail email. Any help will be appreciated, Thanks.

Your indentation suggests that server = .. is in while loop. I guess that is not what you intended. — pyfunc
– pyfunc, Commented Nov 5, 2010 at 3:33
Does your server require authentication? Does it fail silently if it doesn't get it? — Ryan Ginstrom
– Ryan Ginstrom, Commented Nov 5, 2010 at 3:55
I dont have a server, the server I want to send the message to is hotmail which is smtp.live.com:25 — SourD
– SourD, Commented Nov 5, 2010 at 21:15

Rafe Kettler · Accepted Answer · 2010-11-05 05:42:51Z

Your call to smtplib.SMTP() uses invalid arguments. According to the smtplib docs:

SMTP([host[, port[, local_hostname[, timeout]]]])

So, the SMTP constructor takes the optional arguments for hostname, port etc. But you've passed port and hostname as one argument (server = smtplib.SMTP('smtp.live.com:25')).

Provided you have everything else right, if you change that line to read server = smtplib.SMTP('smtp.live.com', 25).

If your server requires authentication (and I suspect it does), before you actually send the email you'll want to call server.login(user, password) to login so you can actually send the message.

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