Image uploading error in PHP

Question

<form action="upload.php" method="post" enctype="multipart/form-data"> Select image to upload: <input type="file" name="fileToUpload" id="fileToUpload"> <input type="submit" value="Upload Image" name="submit"> </form>

Above is my HTML code. Following is my upload PHP code:

<?php $target_dir = "uploads/"; $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]); $uploadOk = 1; $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION); // Check if image file is a actual image or fake image if(isset($_POST["submit"])) { $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]); if($check !== false) { echo "File is an image - " . $check["mime"] . "."; $uploadOk = 1; } else { echo "File is not an image."; $uploadOk = 0; } } ?>

When I upload an image it returns the following:

Warning: getimagesize(): Filename cannot be empty in C:\wamp64\www\company\test\upload.php on line 8

File is not an image.

Is there anything wrong with the code? I am using PHP v5.6.16, please help me.

$_FILES["fileToUpload"]["tmp_name"]);

is empty but,

$_FILES["fileToUpload"]["name"]);

is not empty.

Possible duplicate of Warning: getimagesize() [function.getimagesize]: Filename cannot be empty warning message? — Ravi Hirani
– Ravi Hirani, Commented Mar 10, 2017 at 8:57
I looked into that question. but the thing is $_FILES['fileToUpload']['tmp_name'] is empty. but $_FILES['fileToUpload']['name'] is not empty. why is that?? — Chinthaka Udayasiri
– Chinthaka Udayasiri, Commented Mar 10, 2017 at 9:09

Naincy · Accepted Answer · 2017-03-10 08:50:10Z

if(isset($_POST["submit"]) && isset($_FILES['fileToUpload'])) { $file_temp = $_FILES['fileToUpload']['tmp_name']; $info = getimagesize($file_temp); if($info !== false) { echo "File is an image - " . $info["mime"] . "."; $uploadOk = 1; } else { echo "File is not an image."; $uploadOk = 0; } } else if(isset($_POST["submit"]) && !isset($_FILES['fileToUpload'])) { print "Form was submitted but file wasn't send"; exit; } else { print "Form wasn't submitted!"; exit; }

I did according to your answer.. the thing is $_FILES['fileToUpload']['tmp_name'] is empty, but $_FILES['fileToUpload']['name'] not empty. why is that??

Ravi Hirani · Accepted Answer · 2017-03-10 08:50:34Z

0

You need to check $_FILES is not empty using !empty

if(isset($_POST["submit"]) && !empty($_FILES["fileToUpload"]) { // do your stuff }

OR just check key exist and not null using isset

if (isset($_POST['submit'], $_FILES['fileToUpload'])) { // do your stuff }

answered Mar 10, 2017 at 8:50

Ravi Hirani

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2 Comments

Chinthaka Udayasiri Over a year ago

I did according to your answer.. the thing is $_FILES['fileToUpload']['tmp_name'] is empty, but $_FILES['fileToUpload']['name'] not empty. why is that??

Ravi Hirani Over a year ago

Check this links:- stackoverflow.com/questions/14472741/… and stackoverflow.com/questions/30358737/…

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