Regex match all except a pattern

Question

I need a little help. I already tried to practice in several ways, but it didn't work as expected. For example, this one.

I want to match all single words except the pattern <br> in JS.

So I tried

(?!<br>)[\s\S] (?!<|b|r|>)[\s\S]

The problem I have is, in the ?! quote, it's matching either the first word, < only, not the entire pattern <br>. In reverse, just <br> can match all <br> expect any other words. How can I let it know I want to match the entire word in the ?! quote?

Thank you so much!

Here is what I am trying.

Can you please provide a sample string and your expected output. — RobG
– RobG, Commented May 16, 2017 at 23:06

Washington Guedes · Accepted Answer · 2017-05-17 00:27:16Z

The regular expression you are looking for might look like this:

([^>]|<(?!br>)[^>]+>)+(?=<br>|$)

It should work for any tag, try replacing br by p in the above pattern.

^{Regex101 link}

However, It would be much easier and readable and faster to use:

content.split('<br>').filter(x => x.length)

Hope it helps.

I suggested splitting in the very first comment, but OP did not provide any feedback, and I removed it after some 10th comment. Perhaps, there is something else OP is doing "behind the scenes".

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