Why compiler don't provide default operator= for template class? [duplicate]

Question

My code,

template<typename T> class NamedObject{ public: NamedObject(std::string& name, const T& value):nameValue(name), objectValue(value) { } private: std::string& nameValue; const T objectValue; }; int main(int argc, char* argv[]) { NamedObject<int> obj1(std::string("Obj1"),3); NamedObject<int> obj2(std::string("Obj2"),3); obj2 = obj1; //this line gives error return 0; }

I am getting error,

Error 1 error C2582: 'operator =' function is unavailable in 'NamedObject' c:\users\pkothari\documents\visual studio 2008\projects\stackoflw\stackoflw\stackoflw.cpp 39

I have not provide any operator =, shouldn't compiler provide default one?

@Edit for shown as duplicate: I agree with const, reference can refer to member of another object.

You wrote a non-defaulted constructor, so no compiler provided operator= is generated — Passer By
– Passer By, Commented May 31, 2017 at 4:49
@PasserBy, That's not true. Constructor has nothing to do with operator= — Ajay
– Ajay, Commented May 31, 2017 at 4:50

Ajay · Accepted Answer · 2017-05-31 04:47:30Z

2

Template has nothing to do with it. Your class has a const data member, and has a reference to string. You'd need to remove const attribute has well as reference specifier from the string data member. I would suggest you to implement the class without using templates.

answered May 31, 2017 at 4:47

Ajay

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2 Comments

Pranit Kothari Over a year ago

I know it has nothing to do with Template. I tried removing const as well. But reference can refer to member of another object, right?

Ajay Over a year ago

Reference is not pointer. An int* can point to something else later, but an int& cannot reference to something else later.

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