I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.
This is an example:
$codes = ['tn', 'us', 'fr']; $names = ['Tunisia', 'United States', 'France']; foreach( $codes as $code and $names as $name ) { echo '<option value="' . $code . '">' . $name . '</option>'; } This method didn't work for me. Any suggestions?
foreach( $codes as $code and $names as $name ) { } That is not valid.
You probably want something like this...
foreach( $codes as $index => $code ) { echo '<option value="' . $code . '">' . $names[$index] . '</option>'; } Alternatively, it'd be much easier to make the codes the key of your $names array...
$names = array( 'tn' => 'Tunisia', 'us' => 'United States', ... ); 
foreach operates on only one array at a time.
The way your array is structured, you can array_combine() them into an array of key-value pairs then foreach that single array:
foreach (array_combine($codes, $names) as $code => $name) { echo '<option value="' . $code . '">' . $name . '</option>'; } Or as seen in the other answers, you can hardcode an associative array instead.
array_combine($arr1, array_combine($arr2, $arr3))
string and int values, it won't work for objects, booleans and other arrays.Use array_combine() to fuse the arrays together and iterate over the result.
$countries = array_combine($codes, $names); 
string and int values, it won't work for objects, booleans and other arrays.
array_combine() may not be suitable if the values which become keys are not compatible or become mutated when used as array keys.array_map seems good for this too
$codes = array('tn','us','fr'); $names = array('Tunisia','United States','France'); array_map(function ($code, $name) { echo '<option value="' . $code . '">' . $name . '</option>'; }, $codes, $names); Other benefits are:
If one array is shorter than the other, the callback receive null values to fill in the gap.
You can use more than 2 arrays to iterate through.
array_map() is appropriate when its return value is accessed. When the return data is unneeded, array_walk() is more appropriate.
array_walk() doesn't accept more than one array (to iterate on each element of the 2 arrays at the same time), you may use its 3rd argument $arg, but you will get the whole array in each iteration instead of each of its elements.foreach() would also be more appropriate when no return value is sought.array_walk() is certainly a viable tool for this task as demonstrated by @oLinkWebDevelopment's answer from back in 2014.Use an associative array:
$code_names = array( 'tn' => 'Tunisia', 'us' => 'United States', 'fr' => 'France'); foreach($code_names as $code => $name) { //... } I believe that using an associative array is the most sensible approach as opposed to using array_combine() because once you have an associative array, you can simply use array_keys() or array_values() to get exactly the same array you had before.
array_combine() already produces an associative array, you may want to be clearer about initializing it as associative.string and int values, it won't work for objects, booleans and other arrays.null or float values.This worked for me:
$codes = array('tn', 'us', 'fr'); $names = array('Tunisia', 'United States', 'France'); foreach($codes as $key => $value) { echo "Code is: " . $codes[$key] . " - " . "and Name: " . $names[$key] . "<br>"; } 
$value is simpler to use than $codes[$key].Your code like this is incorrect as foreach only for single array:
<?php $codes = array('tn','us','fr'); $names = array('Tunisia','United States','France'); foreach( $codes as $code and $names as $name ) { echo '<option value="' . $code . '">' . $name . '</option>'; } ?> Alternative, Change to this:
<?php $codes = array('tn','us','fr'); $names = array('Tunisia','United States','France'); $count = 0; foreach($codes as $code) { echo '<option value="' . $code . '">' . $names[count] . '</option>'; $count++; } ?> Walk it out...
$codes = array('tn','us','fr'); $names = array('Tunisia','United States','France'); PHP 5.3+
array_walk($codes, function ($code,$key) use ($names) { echo '<option value="' . $code . '">' . $names[$key] . '</option>'; }); Before PHP 5.3
array_walk($codes, function ($code,$key,$names){ echo '<option value="' . $code . '">' . $names[$key] . '</option>'; },$names); or combine
array_walk(array_combine($codes,$names), function ($name,$code){ echo '<option value="' . $code . '">' . $name . '</option>'; }) in select
array_walk(array_combine($codes,$names), function ($name,$code){ @$opts = '<option value="' . $code . '">' . $name . '</option>'; }) echo "<select>$opts</select>"; 
array_combine() may not be suitable if the values which become keys are not compatible or become mutated when used as array keys.Why not just consolidate into a multi-dimensional associative array? Seems like you are going about this wrong:
$codes = array('tn','us','fr'); $names = array('Tunisia','United States','France'); becomes:
$dropdown = array('tn' => 'Tunisia', 'us' => 'United States', 'fr' => 'France'); 
string and int values, it won't work for objects, booleans and other arrays.array_combine() may not be suitable if the values which become keys are not compatible or become mutated when used as array keys.This will create a dropdown menu from an array and automatically assign its respective value.
<?php $names = array('tn'=>'Tunisia','us'=>'United States','fr'=>'France'); echo '<select name="countries">'; foreach($names AS $let=>$word){ echo '<option value="'.$let.'">'.$word.'</option>'; } echo '</select>'; ?> <select name="countries"> <?php $countries = array('tn'=> "Tunisia", "us"=>'United States',"fr"=>'France'); foreach($countries as $select=>$country_name){ echo '<option value="' . $select . '">' . $country_name . '</option>'; } ?> </select> <?php $my_array = array( 'tn' => 'Tunisia', 'us' => 'United States', 'fr' => 'France' ); echo '<select name="countries">'; echo '<option value="none">Select...</option>'; foreach ($my_array as $k => $v) { echo '<option value="' . $k . '">' . $v . '</option>'; } echo '</select>'; ?> 
You can use array_merge to combine two arrays and then iterate over them.
$array1 = array("foo" => "bar"); $array2 = array("hello" => "world"); $both_arrays = array_merge((array)$array1, (array)$array2); print_r($both_arrays); array_combine() worked great for me while combining $_POST multiple values from multiple form inputs in an attempt to update products quantities in a shopping cart.
array_combine() may not be suitable if the values which become keys are not compatible or become mutated when used as array keys.<?php $codes = array ('tn','us','fr'); $names = array ('Tunisia','United States','France'); echo '<table>'; foreach(array_keys($codes) as $i) { echo '<tr><td>'; echo ($i + 1); echo '</td><td>'; echo $codes[$i]; echo '</td><td>'; echo $names[$i]; echo '</td></tr>'; } echo '</table>'; ?> 
array_keys()) then needs to use the $i variable to access each element from both arrays -- this is not the most elegant approach.foreach only works with a single array. To step through multiple arrays, it's better to use the each() function in a while loop:
while(($code = each($codes)) && ($name = each($names))) { echo '<option value="' . $code['value'] . '">' . $name['value'] . '</option>'; } each() returns information about the current key and value of the array and increments the internal pointer by one, or returns false if it has reached the end of the array. This code would not be dependent upon the two arrays having identical keys or having the same sort of elements. The loop terminates when one of the two arrays is finished.
Instead of foreach loop, try this (only when your arrays have same length).
$number = COUNT($_POST["codes "]);//count how many arrays available if($number > 0) { for($i=0; $i<$number; $i++)//loop thru each arrays { $codes =$_POST['codes'][$i]; $names =$_POST['names'][$i]; //ur code in here } } 
foreach() means that you don't have to count the array and maintain a counter variable. A foreach() will not be entered if the count is 0.i gave a simple example
class Parallel implements Iterator { private int $index; private array $arrays; private int $countAny; public function __construct(array ...$arrays) { $this->countAny = count($arrays[0]); $this->arrays = $arrays; } #[\Override] public function current(): array { $return = []; foreach ($this->arrays as $array) { $return[] = $array[$this->index]; } return $return; } #[\Override] public function next(): void { $this->index++; } #[\Override] public function key(): mixed { return $this->index; } #[\Override] public function valid(): bool { return $this->index < $this->countAny; } #[\Override] public function rewind(): void { $this->index = 0; } } $parallel = new Parallel( [1, 2, 3, 4], ['a', 'b', 'c', 'd'], ['london', 'paris', 'rome', 'istanbul'], ); foreach ($parallel as [$number, $word, $city]) { echo PHP_EOL; printf('Number: %s, Word: %s, City: %s', $number, $word, $city); } I solved a problem like yours by this way:
foreach(array_keys($idarr) as $i) { echo "Student ID: ".$idarr[$i]."<br />"; echo "Present: ".$presentarr[$i]."<br />"; echo "Reason: ".$reasonarr[$i]."<br />"; echo "Mark: ".$markarr[$i]."<br />"; } 
array_keys()) then needs to use the $i variable to access each element from both arrays -- this is not the most elegant approach.You should try this for the putting 2 array in singlr foreach loop Suppose i have 2 Array 1.$item_nm 2.$item_qty
`<?php $i=1; ?> <table><tr><td>Sr.No</td> <td>item_nm</td> <td>item_qty</td> </tr> @foreach (array_combine($item_nm, $item_qty) as $item_nm => $item_qty) <tr> <td> $i++ </td> <td> $item_nm </td> <td> $item_qty </td> </tr></table> @endforeach ` 
array_combine() may not be suitable if the values which become keys are not compatible or become mutated when used as array keys.I think that you can do something like:
$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');
foreach ($codes as $key => $code) { echo '<option value="' . $code . '">' . $names[$key] . '</option>'; } It should also work for associative arrays.
I think the simplest way is just to use the for loop this way:
$codes = array('tn','us','fr'); $names = array('Tunisia','United States','France'); for($i = 0; $i < sizeof($codes); $i++){ echo '<option value="' . $codes[$i] . '">' . $names[$i] . '</option>'; } foreach() means that you don't have to count the array and maintain a counter variable.foreach() you will still need the key which is basically the index...foreach() is the most elegant and concise way -- it automatically handles the changing of the key values, isn't limited to working with indexed arrays, and you only need to use the key to access the "other" array element because the value of the iterated array is more conveniently available by the foreach's value variable.En laravel Livewire
return view('you_name_view', compact('data','data2')); @foreach ($data as $index => $data ) <li> <span>{{$data}}</span> <span>{{$data2[$index]}}</span> </li> @endforeach 
if(isset($_POST['doors'])=== true){ $doors = $_POST['doors']; }else{$doors = 0;} if(isset($_POST['windows'])=== true){ $windows = $_POST['windows']; }else{$windows = 0;} foreach($doors as $a => $b){ Now you can use $a for each array....
$doors[$a] $windows[$a] .... } Few arrays can also be iterated like this:
foreach($array1 as $key=>$val){ // Loop though one array $val2 = $array2[$key]; // Get the values from the other arrays $val3 = $array3[$key]; $result[] = array( //Save result in third array 'id' => $val, 'quant' => $val2, 'name' => $val3, ); } This will only work if the both array have same count.I try in laravel, for inserting both array in mysql db
$answer = {"0":"0","1":"1","2":"0","3":"0","4":"1"};
$reason_id = {"0":"17","1":"19","2":"15","3":"19","4":"18"};
$k= (array)json_decode($answer); $x =(array)json_decode($reason_id); $number = COUNT(json_decode($reason_id, true)); if($number > 0) { for($i=0; $i<$number; $i++) { $val = new ModelName(); $val->reason_id = $x[$i]; $val->answer =$k[$i]; $val->save(); } } 
for() loop was already posted earlier.To avoid referencing values by index and risking data corruption by using one array's values as keys via array_combine(), you can use array_map() to iterate two or more arrays at the same time.
Codes: (Demo)
Implode an array populated with options tags without parameters in callabck signature:
echo implode( "\n", array_map( fn() => vsprintf('<option value="%s">%s</option>', func_get_args()), $codes, $names ) ); Implode an array populated with options by accumulating passed-in values with the spread operator:
echo implode( "\n", array_map( fn(...$values) => vsprintf('<option value="%s">%s</option>', $values), $codes, $names ) ); Transpose two or more arrays, then iterate and print the row data from the 2d array:
foreach (array_map(null, $codes, $names) as $codeName) { vprintf('<option value="%s">%s</option>' . "\n", $codeName); } Using printf() family functions voids concatenation and interpolation. When creating strings containing quotes, this can help your code to be more readable.
it works for me
$counter = 0; foreach($codes as $code) { $codes_array[$counter]=$code; $counter++; } $counter = 0; foreach($names as $name) { echo $codes_array[$counter]."and".$name; $counter++; } 