Run function and keep loop running c++

Question

How to run a function within loop and still keep loop running without waiting when the function2 completes?

int main(){ function1(); } function1(){ while(1){ function2(); } } function2(){ //some task that needs to do independently while, While loop runs }

You need multiple threads. en.cppreference.com/w/cpp/thread/thread — 0x5453
– 0x5453, Commented Jun 29, 2017 at 14:12
So you want to run function1() and function2() at the same time? — Javia1492
– Javia1492, Commented Jun 29, 2017 at 14:13
Do you realize that if you don't wait for function2(), you're going to get a lot of instances of it running simultaneously. — HolyBlackCat
– HolyBlackCat, Commented Jun 29, 2017 at 14:13

Hatted Rooster · Accepted Answer · 2017-06-29 14:16:07Z

You can launch function2 async:

#include <future> void function1(){ while(1){ std::async(std::launch::async, function2); } }

Do note that this will generate a lot of instances that all call function2(), you should probably throttle that.

But, will this block the main thread forever since you didn't assign the result of std::async to the std::future instance?

GavinHenderson5 · Accepted Answer · 2017-06-29 15:06:31Z

Spawn a new thread with function2 and then start them in function 1 in the loop where you previously called it. It should compile but it will spawn infinite threads and something will go wrong so be careful. Sounds like threading is your solution though

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