php variable converting to JSON object

Question

I want to make an array of json objects having the structure as follows:

{ "client-mac": "0C:D2:B5:68:73:24", "client-dbm": "-82", "clientManuf": "unknown" }

I am using following php code to get this result:

$clientMac = $clients->{'client-mac'}; $clientStrength = $clients->{'snr-info'}->{'last_signal_dbm'}; $clientManuf = $clients->{'client-manuf'}; $jsonObject = array('client-mac' => $clientMac, 'client-dbm' => $clientStrength, 'clientManuf' => $clientManuf); $jsonString = json_encode($jsonObject);

The problem is I am getting following json string:

{"client-mac":{ "0":"0C:D2:B5:68:73:24" }, "client-dbm":{ "0":"-82" }, "clientManuf":{"0":"Unknown"} }

Why I am getting those extra keys as "0"? And how can I get my desired output? Thank you in advance :)

trincot · Accepted Answer · 2017-07-22 14:32:18Z

Apparently your source data has one more nested level with one key/value pair.

You could use reset on them to just pick the first value from that:

array('client-mac' => reset($clientMac), 'client-dbm' => reset($clientStrength), 'clientManuf' => reset($clientManuf));

Rajdeep Paul · Accepted Answer · 2017-07-22 14:31:49Z

That's because $clientMac, $clientStrength and $clientManuf are objects, not literal strings. You have to change the first three lines in the following way,

$clientMac = $clients->{'client-mac'}->{'0'}; $clientStrength = $clients->{'snr-info'}->{'last_signal_dbm'}->{'0'}; $clientManuf = $clients->{'client-manuf'}->{'0'}; ...

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