Search and Replace under linux?

Question

I tried the following but not adding '' this example

I want to replace FILENAME_LOGIN to 'login.php'

Tried this:

grep -r "login.php" -l | tr '\n' ' ' | xargs sed -i 's/"login.php"/'login.php'/g'

However, it gives me login.php not 'login.php'

Thanks

Untested, but try to escape the single quotes: xargs sed -i 's/"login.php"/\'login.php\'/g' - or double-escape: xargs sed -i 's/"login.php"/\\'login.php\\'/g' — Paulo Scardine
– Paulo Scardine, Commented Sep 4, 2017 at 14:13
You can't include single quotes in a single-quote delimited script, no matter how many times you try to escape them. — Ed Morton
– Ed Morton, Commented Sep 4, 2017 at 16:07

campovski · Accepted Answer · 2017-09-04 14:14:59Z

1

You only need sed for this:

sed -i -e "s/FILENAME_LOGIN/'login.php'/g" /your/file

answered Sep 4, 2017 at 14:14

campovski

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Thomas Mccaffery · Accepted Answer · 2017-09-04 14:42:12Z

0

I figured it out:

find ./ -type f -exec sed -i -e 's/FILENAME_LOGIN/'login.php'/g' {} \;

answered Sep 4, 2017 at 14:42

Thomas Mccaffery

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2 Comments

campovski Over a year ago

Yes, this will search in files in any subdirectory, nice! :)

Ed Morton Over a year ago

it won't add single quotes around the text though.

Ed Morton · Accepted Answer · 2017-09-04 16:08:09Z

0

find ./ -type f -exec sed -i -e 's/FILENAME_LOGIN/'\''login.php'\''/g' {} \;

answered Sep 4, 2017 at 16:08

Ed Morton

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1 Comment

Toby Speight Over a year ago

Thank you for this code snippet, which may provide some immediate help. A proper explanation would greatly improve its educational value by showing why this is a good solution to the problem, and would make it more useful to future readers with similar, but not identical, questions. Even something as simple as "You forgot to quote the ' characters" would be a great improvement.

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