Cannot convert value of type Substring to expected argument type String - Swift 4

Question

Trying to get substring of String and append it to array of Strings:

var stringToSplit = "TEST TEXT" var s = [String]() let subStr = anotherString[0 ..< 6] s.append(subStr) // <---- HERE I GET THE ERROR

Just initialize a new String with your substring s.append(String(subStr)) — Leo Dabus
– Leo Dabus, Commented Sep 22, 2017 at 6:19

MBH · Accepted Answer · 2017-09-22 08:36:30Z

47

As @Leo Dabus mentioned, you need to initialize a new String with your substring:

Change:

s.append(subStr)

To:

s.append(String(subStr))

edited Sep 22, 2017 at 8:36

MBH

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answered Sep 22, 2017 at 6:23

Rashwan L

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1 Comment

vikzilla Over a year ago

Awesome - I was having difficulty figuring out how to convert a String.subsequence but this is simple and effective. Take my upvote

ingconti · Accepted Answer · 2022-02-02 19:22:06Z

my two cents for serro in different context. I was trying to get an array of "String" splitting a string. "split" gives back "Substring", for efficiency reason (as per Swift.org litre).

So I ended up doing:

let buffer = "one,two,three" let rows = buffer.split(separator:",") let realStrings = rows.map { subString -> String in return String(subString) } print(realStrings)

Ape can help someone else.

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