Calling a function that returns its updated output python

Question

So I'm completely having a brain fart but I'm attempting to call a function that returns its own updated input in a for loop that has to run 30 times. I have the for loop part down I'm just not sure how to call the function correctly.

def miniopoloy_turn(state, cash) return state, cash

so the function returns its updated state and cash values after running, but how would I then run the function again with the updated output inside a for loop?

I mean in this case its actually referring to money, like cash... — andrew fay
– andrew fay, Commented Sep 23, 2017 at 20:10

user4815162342 · Accepted Answer · 2017-09-23 20:25:49Z

2

It sounds like you need to simply store the returned values in local variables and re-run the function as many times as necessary:

# 1. set up initial values state = ... cash = ... # 2. run the function iteratively for i in xrange(30): state, cash = miniopoly_turn(state, cash) print state, cash # 3. profit!

edited Sep 23, 2017 at 20:25

answered Sep 23, 2017 at 20:13

user4815162342

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2 Comments

andrew fay Over a year ago

So in this case state and cash will be updated with each iteration of the loop and the function will run with the updated values? Man I had this exact code and overthought it and didn't think it would work like this... Thanks!

user4815162342 Over a year ago

@andrewfay Exactly. The alternative is to use global variables.

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