I have a spring boot web application which I run using java -jar application.jar. I need to get the jar parent folder path dynamically from the code. How can I accomplish that?
I have already tried this, but without success.
3 Answers
Well, what have worked for me was an adaptation of this answer. The code is:
if you run using java -jar myapp.jar dirtyPath will be something close to this: jar:file:/D:/arquivos/repositorio/myapp/trunk/target/myapp-1.0.3-RELEASE.jar!/BOOT-INF/classes!/br/com/cancastilho/service. Or if you run from Spring Tools Suit, something like this: file:/D:/arquivos/repositorio/myapp/trunk/target/classes/br/com/cancastilho/service
public String getParentDirectoryFromJar() { String dirtyPath = getClass().getResource("").toString(); String jarPath = dirtyPath.replaceAll("^.*file:/", ""); //removes file:/ and everything before it jarPath = jarPath.replaceAll("jar!.*", "jar"); //removes everything after .jar, if .jar exists in dirtyPath jarPath = jarPath.replaceAll("%20", " "); //necessary if path has spaces within if (!jarPath.endsWith(".jar")) { // this is needed if you plan to run the app using Spring Tools Suit play button. jarPath = jarPath.replaceAll("/classes/.*", "/classes/"); } String directoryPath = Paths.get(jarPath).getParent().toString(); //Paths - from java 8 return directoryPath; } EDIT:
Actually, if your using spring boot, you could just use the ApplicationHome class like this:
ApplicationHome home = new ApplicationHome(MyMainSpringBootApplication.class); home.getDir(); // returns the folder where the jar is. This is what I wanted. home.getSource(); // returns the jar absolute path. 
Comments
File file = new File("."); logger.debug(file.getAbsolutePath()); This worked for me to get the path where my jar is running, I hope this is what you are expecting.
2 Comments
Carlos N.
This code will return the folder path where I issued the java -jar command. If I run it from my target folder: cd D:\arquivos\repositorio\myapp\trunk\target java -jar application.jar I'll get this result:
D:\arquivos\repositorio\myapp\trunk\target\. If I run it from an outside folder, let's say: cd D:\arquivos\repositorio\myapp\trunk\ java -jar target\application.jar I'll get: D:\arquivos\repositorio\myapp\trunk\. It partially solves my problem. Is there a way to find the path even if I issue the command from another external folder?
mohdnaveed
Will this not keep on creating new files of . everytime the script is run?
Try this code
public static String getParentRealPath(URI uri) throws URISyntaxException { if (!"jar".equals(uri.getScheme())) return new File(uri).getParent(); do { uri = new URI(uri.getSchemeSpecificPart()); } while ("jar".equals(uri.getScheme())); File file = new File(uri); do { while (!file.getName().endsWith(".jar!")) file = file.getParentFile(); String path = file.toURI().toString(); uri = new URI(path.substring(0, path.length() - 1)); file = new File(uri); } while (!file.exists()); return file.getParent(); } URI uri = clazz.getProtectionDomain().getCodeSource().getLocation().toURI(); System.out.println(getParentRealPath(uri)); 
MyCustomClass.class.getProtectionDomain().getCodeSource().getLocation().toURI().getPath();If I run the application using Spring Tools Suit IDE play button, the result of this code will be:/D:/arquivos/repositorio/myapp/trunk/target/classes/