bash script on padding 0 on digit with character

Question

I want to write a bash scritpt where it will put 0 padding infront of a hexadecimal character eg. 32b, ae2, etc. it works on just integer but not on mix character and digit. I used

printf "%04d$a\n" . a=ae2.

what I want to happen is like this 0ab3, 003s, 000a, 002a padding

Yoory N. · Accepted Answer · 2017-11-10 08:58:26Z

I would suggest this:

printf '%04x\n' "0x${a}"

x in format specification stands for hexadecimal integer (lowercase). And without 0x prefix in argument bash will complain that ae2 is an invalid number.

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