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I am new to python and trying to figure out how to do things the "right way" and encountered the following problem:

My project has a structure that looks a little this:

├─packageA │ functions.py │ __init__.py │ └─tests some_tests.py 

packageA/__init__.py is empty.

packageA/functions.py looks like this:

def some_function(x): return x*x 

And finally, tests/some_tests.py:

import packageA.functions if __name__ == '__main__': print(packageA.functions.some_function(2)) 

If I run test.py using pycharm it works fine. However, when I open up a console and start it by running python.exe ./tests/some_tests.py I get

 Traceback (most recent call last): File ".\tests\some_tests.py", line 1, in <module> import packageA.functions ModuleNotFoundError: No module named 'packageA' 

While writing this, I figured out that pycharm adds source folders to PYTHONPATH - when I turn this off I get the same error. Is the folder structure above a sensible way to structure a python project? If not, how should it be organized instead?

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  • You can leave your folder structure if it is if you use the standard unittest module for your tests. Then the tests can be run with python -m unittest from the root directory and the import of packageA succeeds. I am not sure why this works, while python ./tests/some_tests.py does not. Can someone enlighten me? Edit: stackoverflow.com/a/24266885/6095394 gave me the answer: The TestLoader of the unittest module adds the package directory to sys.path. Commented Feb 4, 2018 at 13:38

1 Answer 1

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There are several options. However, the accepted answer in a similar SO question isn't ideal.

The below answer addresses your issue by explicitly adding the parent directory path at the start of your sys.path list.

import os, sys, inspect currentdir = os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe()))) parentdir = os.path.dirname(currentdir) sys.path.insert(0, parentdir) import packageA.functions 
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