Looping over the last few entries of an array

Question

I'm trying to have a forEach loop over an array, but only the last few entries.

I'd know how to do this in a for loop, that'd look a bit like this:

var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]; /* This will loop over the last 3 entries */ for(var x = arr.length; x >= 7; x--){ console.log(arr[x]); }

Would there be any way of achieving the same results in a forEach loop?

No there is absolutely no way that you can do this with a .forEach() loop. — Redu
– Redu, Commented Apr 23, 2018 at 19:23

Nenad Vracar · Accepted Answer · 2018-02-04 17:33:45Z

2

You can use slice() and reverse() methods and then forEach() loop on that new array.

var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]; arr.slice(-3).reverse().forEach(e => console.log(e))

answered Feb 4, 2018 at 17:33

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2 Comments

That's actually a pretty smart way of doing this! Thanks!

note the users output produces undefined, 10, 9, 8 not sure if that is intentional or not

Aaditya Thakkar · Accepted Answer · 2018-02-04 17:35:26Z

0

This is how you do it with forEach loop:

var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]; arr.forEach((element, index) => { if(index>7) console.log(arr[index]); })

answered Feb 4, 2018 at 17:35

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Code dumps are not useful answers. Say what you did, and more importantly why. But note that you're visiting the entries in the wrong order.

Nina Scholz · Accepted Answer · 2018-02-04 17:45:40Z

You could take a classic approach by taking the count of the last elements and use it as counter and an offset for the index.

Then loop with while by decrementing and checking the counter.

var array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], last = 3, offset = array.length - last; while (last--) { console.log(array[last + offset]); }